First, we'll want to write out the equation
![9 \frac{4}{9} < n < \sqrt{144}](https://tex.z-dn.net/?f=9%20%5Cfrac%7B4%7D%7B9%7D%20%3C%20n%20%3C%20%5Csqrt%7B144%7D%20)
then reduce what we can
![9 \frac{4}{9} < n < 12](https://tex.z-dn.net/?f=9%20%5Cfrac%7B4%7D%7B9%7D%20%3C%20n%20%3C%2012)
so this means n can equal any whole number between 9 4/9 & 12, which gives us the options of {10,11}
It’s A
:) hope it’s right!!!
Answer:I think the first one is c and I think the second one is c
Step-by-step explanation:
The second one might be be but most likely C
Answer:
144
Step-by-step explanation:
Answer:
50,803,200 ways
Step-by-step explanation:
In this situation, since you should alternate girl-boy or boy-girl, the line-up can either start with a boy or a girl kicking which would yield one of the two following patterns:
BGBGBGBGBGBGBG or GBGBGBGBGBGBGB.
For each of those patterns, there are 7! ways to arrange all boys and 7! ways to arrange all girls. The number of ways that a line-up can be made for one round of kicking is:
![n=2*7!*7!\\n=2*(7*6*5*4*3*2)^2\\n=50,803,200\ ways](https://tex.z-dn.net/?f=n%3D2%2A7%21%2A7%21%5C%5Cn%3D2%2A%287%2A6%2A5%2A4%2A3%2A2%29%5E2%5C%5Cn%3D50%2C803%2C200%5C%20ways)
There are 50,803,200 ways to set the line-up.