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Phantasy [73]
2 years ago
12

On a Sunday , a football team give away souvenir footballs to each person entering the football stadium. one group received 42 f

ootballs. A second group received 54 souvenir footballs . If each person entering the stadium received the same number of footballs , what was the greatest possible number of footballs that each ñ person could have received
Mathematics
1 answer:
adell [148]2 years ago
3 0

Using the greatest common factor, it is found that the greatest possible number of footballs that each could have received is of 6.

<h3>Greatest common factor:</h3>
  • To find the greatest possible value divided equally between two amounts, we have to find the greatest common factor of the two amounts.

In this problem, the amounts of footballs are of 42 and 54, hence:

42 - 54|2

21 - 27|3

7 - 9

Then, gcf(42, 54) = 2 x 3 = 6, which means that the greatest possible number of footballs that each could have received is of 6.

To learn more about the greatest common factor, you can take a look at brainly.com/question/7527348

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P(X \geq 1)= 1-P(X

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

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Solution to the problem

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X \sim Binom(n=10, p=0.15)

what is the probability that no errors are made?

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P(X=0)=(10C10)(0.15)^{0} (1-0.15)^{10-0}=0.1969

what is the probability that at least one error made?

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P(X \geq 1)

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P(X \geq 1)= 1-P(X

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