Ask question

Ask question

All categories

4 years ago

9

What steps do I take for this

1 answer:

Luden [163]4 years ago

7 0

First, divide the shape into two figures ( a semicircle and a rectangle)
Then, find the are or the two shapes using the area formula for a semicircle ( $\frac{ \pi r^{2} }{2}$ ) and the are formula for a rectangle (base x height)
Finally, add the two areas together and you have your answer

You might be interested in

Write what the expressions below best represent within the context of the word problem.

malfutka [58]

The answer to this is 2 nickles and 6 quarters

5 0

3 years ago

What is 6.92 x 10-3 written in standard form?

dem82 [27]

The standard form is 0.00692

3 0

4 years ago

Given: x ∥ y and w is a transversal Prove: ∠3 ≅ ∠6 Parallel lines x and y are cut by transversal w. On line x where it intersect

SOVA2 [1]

Answer:

The missing reason in the proof is transitive property

Step-by-step explanation:

<u>Statement </u> <u>Reason </u>

1. x ∥ y w is a transversal 1. given

2. ∠2 ≅ ∠3 2. def. of vert. ∠s

3. ∠2 ≅ ∠6 3. def. of corr. ∠s

4. ∠3 ≅ ∠6 4. ??????????

From the statements 2 and 3

The previous proved statement to make use of the transitive property reason or proof

∴ 4. ∠3 ≅ ∠6 4. transitive property

Note: the transitive property states that: If a = b and b = c, then a = c.

6 0

3 years ago

Read 2 more answers

You have 32 cups of milk. You need 1.25 cups to make one serving of deep-fried chicken. How many servings can you make? Whole se

sashaice [31]

Answer:

25 cups and 3/5 of a cup

Step-by-step explanation:

Bro trust me

3 0

3 years ago

Read 2 more answers

If tanA+cotA=2 then find the value of cosA

aniked [119]

Answer:

cos A=

$\frac{1}{ \sqrt{2} }$

Step-by-step explanation:

We know,

cotA=

$\frac{1}{ \tan(a) }$

Substituting the value of cot A in the given equation, we get

$\tan( a) + \frac{1}{ \tan(a) } = 2$

$\frac{{ \tan }^{2} a + 1}{ \: \tan(a) } = 2$

${ \tan }^{2 \: } a \: + 1 = 2 tan \: a$

${ \tan }^{2} a - 2 \tan \: a + 1 = 0$

$( \tan \: a - 1) {}^{2 } = 0$

$\tan \: a - 1 = \sqrt{0}$

$\tan \: a = 1$

$\tan \: a \: = \tan \: 45$

$a = 45$

$\cos \: a = \cos \: 45$

$\cos \: a = \frac{1}{ \sqrt{2} }$

4 0

3 years ago