Answer:
4.46% probability that the pressure will exceed this value.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Gaussian distribution with a mean value of 69 psi and a standard deviation of 10 psi.
Gaussian distribution = normal.
This means that 
If it is important that the pressure stays below 86 psi, what is the probability (in percent) that the pressure will exceed this value?
As a proportion, this probability is 1 subtracted by the pvalue of Z when X = 86. So



has a pvalue of 0.9554
1 - 0.9554 = 0.0446
0.0446*100 = 4.46%
4.46% probability that the pressure will exceed this value.
Answer:
$27.14
Step-by-step explanation:
Price of 1 DVD: $9.10
Price of 4 DVDs: 4 * $9.10 = $36.40
Discount: 25%
Now we find 25% of $36.40.
25% of $36.40 =
= 0.25 * $36.40
= $9.10
The 25% discount amounts to $9.10. We now subtract $9.10 from $36.40 to find the discounted price.
$36.40 - $9.10 = $27.30
Now we need to apply the 6.75% tax to $27.30.
6.75% of $27.30 =
= 0.0675 * $27.30
= $1.84
The sales tax is $1.84.
Now we add the sales tax amount to the total discounted price.
$27.30 + $1.84 = $29.14
Answer: $27.14
Answer:
ax + ab
Step-by-step explanation:
Step 1: Write expression
a(x + b)
Step 2: Distribute a to each term
ax + ab
Answer:50%
Step-by-step explanation:
Answer:
The answer = 8.1841 cm²
Step-by-step explanation:
Sector of area = <u>46⁰</u> pie14²
360⁰
Area of the showed region = 78.6794 - 1/2 × 14 × 14 × sin46⁰
= <u>8.1841cm</u><u>²</u>
<u>MARK</u><u> </u><u>BRAINLIEST</u><u> </u>