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KatRina [158]
3 years ago
9

class="latex-formula">

​
Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
4 0

Answer: 21.9

131.4 divided by 6

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X / 2 = 7 find what x represents
Masteriza [31]

Answer:

x = 14

Step-by-step explanation:

X / 2 = 7

Multiply by 2 to isolate x.

x = 7 * 2

x = 14

3 0
3 years ago
Which of the following represents the factorization of the polynomial below?<br> 2x2 +11x +5
beks73 [17]

Answer:

(2x + 1)(x + 5)

Step-by-step explanation:

2x² + 11x + 5 =

= 2x² + 10x + x + 5

= 2x(x + 5) + (x + 5)

= (2x + 1)(x + 5)

3 0
3 years ago
What two sums are equal to 3 3/4? Pls show work.
Rina8888 [55]
3 + 3/4 = 3 3/4

Ans: 3 and 3/4

2 + 1 3/4 = 3 3/4

Ans: 2 and 1 3/4
5 0
3 years ago
Suppose f is a continuous function on [-2, 2) such that
Leviafan [203]

Answer:

2. a and b only.

Step-by-step explanation:

We can check all of the given conditions to see which is true and which false.

a. f(c)=0 for some c in (-2,2).

According to the intermediate value theorem this must be true, since the extreme values of the function are f(-2)=1 and f(2)=-1, so according to the theorem, there must be one x-value for which f(x)=0 (middle value between the extreme values) if the function is continuous.

b. the graph of f(-x)+x crosses the x-axis on (-2,2)

Let's test this condition, we will substitute x for the given values on the interval so we get:

f(-(-2))+(-2)

f(2)-2

-1-1=-3  lower limit

f(-2)+2

1+2=3 higher limit

according to these results, the graph must cross the x-axis at some point so the graph can move from f(x)=-3 to f(x)=3, so this must be true.

c. f(c)<1 for all c in (-2,2)

even though this might be true for some x-values of of the interval, there are some other points where this might not be the case. You can find one of those situations when finding f(-2)=1, which is a positive value of f(c), so this must be false.

The final answer is then 2. a and b only.

4 0
3 years ago
PROVE THESE TRIANGLES ARE CONGRUENT
jenyasd209 [6]

Answer:

These triangles cannot be proved congruent

Step-by-step explanation:

The theorems for congruence are  SSS SAS ASA AAS. Here, there is only one common side and one common angle marked, therefore you cannot prove congruency.

8 0
2 years ago
Read 2 more answers
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