Answer:
28.11
Step-by-step explanation:
Answer:
The pairs of integer having two real solution for
are




Step-by-step explanation:
Given

Now we will solve the equation by putting all the 6 pairs so we get the following
for 
for 
for 
for 
for 
for 
The above all are Quadratic equations inn general form 
where we have a,b and c constant values
So for a real Solution we must have

for
we have
which is less than 0 ∴ not a real solution.
for
we have
which is greater than 0 ∴ a real solution.
for
we have
which is greater than 0 ∴ a real solution.
for
we have
which is greater than 0 ∴ a real solution.
for
we have
which is equal to 0 ∴ a real solution.
for
we have
which is less than 0 ∴ not a real solution.
The answer is a
i hope this helps
Answer:
B. $5039.58
Step-by-step explanation:
compound interest formula: amount = p(1 + \frac{r}{n})^{nt}
p= principal ($2,300)
r= interest rate as a decimal (4% = 0.04)
n= number of times the principal is compounded per year (annually = onceper year so 1 time per year)
t= time in years (20 years)
new equation: amount = 2300(1+\frac{0.04}{1} )^{1*20}
That equation equals $2,739.58 which you add to the principal.
$2,739.58 + $2,300 = $5039.58
hope this helps :)
Answer:
(0,-4)
Step-by-step explanation: