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UNO [17]
3 years ago
14

What is the length of a rectangle whose width in 17 inches and whose area is 582.25 in?

Mathematics
2 answers:
Marina CMI [18]3 years ago
6 0
We know, area = length * width
Here, A = 582.25 in²
w = 17 in

Substitute their values, 
582.25 = l * 17
l = 582.25 / 17
l = 34.25 in

In short, Your Answer would be 34.25 inches

Hope this helps!
photoshop1234 [79]3 years ago
6 0

The length of a rectangle whose width in 17 inches and whose area is 582.25 in is 34.25 inch

<h3>Further explanation </h3>

Rectangle is a quadrilateral with four right angles. Rectangle can also be defined as an equiangular quadrilateral, because equiangular means that all of its angles are equal. Rectangle can also be defined as a parallelogram containing a right angle.

To find the width of a rectangle, we can use the formula:

We can plug the area and length of the rectangle into the formula and solve for the width.

area = length * width.

If you don't have the area, you can use the rectangle's perimeter instead.

Area is measured in square units, such as square inches, square feet or square meters. To find the area of a rectangle, we can multiply the length by the width.

A = L * W

where where A is the area, L is the length, W is the width.

Therefore, the length of a rectangle is

\frac{area }{width } = \frac{582.25 in}{17 inches} = 34.25 inches

<h3>Learn more</h3>
  1. Learn more about rectangle brainly.com/question/2289670
  2. Learn more about width brainly.com/question/7604404
  3. Learn more   about area brainly.com/question/468878

<h3>Answer details</h3>

Grade:  5

Subject:  Math

Chapter:   the length of a rectangle

Keywords: rectangle, width, area, length, inch

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