What is the length of a rectangle whose width in 17 inches and whose area is 582.25 in?
2 answers:
The length of a rectangle whose width in 17 inches and whose area is 582.25 in is 34.25 inch
<h3>Further explanation </h3>Rectangle is a quadrilateral with four right angles. Rectangle can also be defined as an equiangular quadrilateral, because equiangular means that all of its angles are equal. Rectangle can also be defined as a parallelogram containing a right angle.
To find the width of a rectangle, we can use the formula:
We can plug the area and length of the rectangle into the formula and solve for the width.
If you don't have the area, you can use the rectangle's perimeter instead.
Area is measured in square units, such as square inches, square feet or square meters. To find the area of a rectangle, we can multiply the length by the width.
where where A is the area, L is the length, W is the width.
Therefore, the length of a rectangle is
- Learn more about rectangle brainly.com/question/2289670
- Learn more about width brainly.com/question/7604404
- Learn more about area brainly.com/question/468878
<h3>Answer details</h3>
Grade: 5
Subject: Math
Chapter: the length of a rectangle
Keywords: rectangle, width, area, length, inch
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Suggesting that you want this in standard form, in terms of quadratic equations, you would technically follow a process similar if not almost exactly like the 2 - step equation method with the exception of separating the (x)s and the equations to find x and then plug it in and what-not.
With that being said you would subtract 5 in (x+5) from said 5 in the second equation and -10 in the first equation in order to get 2x^2+7x-15, you would continue to do the same for the x by subtracting it from both ends making the 7x a 6x because there is a 1 at the beginning of each x if there is no number that is shown already. Which finally gives you the equation (y= 2x^2+6x-15)
Suggesting that you want this in standard form, in terms of quadratic equations, you would technically follow a process similar if not almost exactly like the 2 - step equation method with the exception of separating the (x)s and the equations to find x and then plug it in and what-not.
With that being said you would subtract 5 in (x+5) from said 5 in the second equation and -10 in the first equation in order to get 2x^2+7x-15, you would continue to do the same for the x by subtracting it from both ends making the 7x a 6x because there is a 1 at the beginning of each x if there is no number that is shown already. Which finally gives you the equation (y= 2x^2+6x-15)