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2 years ago

How do you solve for the x?

Mathematics

1 answer:

Norma-Jean [14]2 years ago

4 0

when we simplfy 3x^2-4x-20=0 then by using quadratic formula we get x=2 Or x=-10/3

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If three hats cost 24.30 how much is 1 hat

Katen [24]

Just cross multiply basically divide

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2 years ago

Chris sold red and blue pens for a.

mina [271]

Answer: 7 i think

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

I am a number greater than 40,000 and less than 60,000. My ones digit and tens digit are the same. My ten-thousands digit is 1 l

jarptica [38.1K]

I am a number greater than 40,000 and less than 60,000:

40,000 < n < 60,000

This means that:

n = 10,000n₁ + 1,000n₂ + 100n₃ + 11n₄

And also:

4 ≤ n₁ < 6

0 ≤ n₂ ≤ 9

0 ≤ n₃ ≤ 9

0 ≤ n₄ ≤ 9

My ten thousands digit is 1 less than 3 times the sum of my ones digit and tens digit:

n₁ = 3*2n₄ - 1

n₁ = 6n₄ - 1

This means that:

n = 10,000*(6n₄-1) + 1,000n₂ + 100n₃ + 11n₄

n = 60,000n₄ - 10,000 + 1,000n₂ + 100n₃ + 11n₄

n = 60,011n₄ - 10,000 + 1,000n₂ + 100n₃

My thousands digit is half my hundreds digit, and the sum of those two digits is 9:

n₂ = 1/2 * n₃

n₂ + n₃ = 9

Therefore:

n₂ = 9 - n₃

Therefore:

9 - n₃ = 1/2 * n₃

9 = 1/2 * n₃ + n₃

9 = 1.5 * n₃

Therefore:

n₃ = 6

If n₃=6, n₂=3.

This means that:

n = 60,011n₄ - 10,000 + 1,000*3 + 100*6

n = 60,011n₄ - 10,000 + 3,000 + 600

n = 60,011n₄ - 6,400

Therefore:

0<n₄<2, so n₄=1.

If n₄=1:

n = 60,011 - 6,400

n = 53,611

Answer:

53,611

3 0

2 years ago

A circle with radius of 5 cm sits inside a 11 cm * 11 cm rectangle.

Nadusha1986 [10]

Answer:

42.43 $cm^{2}$

Step-by-step explanation:

Given:

A circle with a radius of 5 cm sits inside a 11 cm x 11 cm rectangle.

Question asked:

What is the area of the shaded region as shown in the figure ?

Solution:

First of all calculate area of circle and then area of rectangle:-

$Area\ of\ cirle=\pi r^{2}$

$=\frac{22}{7} \times5\times5\\ \\ =\frac{550}{7}\\ \\=78.571\ cm^{2}\\$

As here length an width both are 11 cm, we can say that this is a square.

$Area\ of\ square=(Side)^{2}$

$=11\times11=121\ cm^{2}$

Now, area of shaded region = Area of square - Area of circle

= 121 - 78.571 = 42.429 $cm^{2}$

Therefore, the area of the shaded region will be 42.43 $cm^{2}$

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5 0

2 years ago

Use the law of Sines to find the missing angle of the triangle. Find m

Whitepunk [10]

Ah...Trigonometry is fun!

The law of sines states:
$\frac{sinA}{a}= \frac{sinB}{b} = \frac{sinC}{c}$
The transitive property (switching the orders of the equations) applies here. Therfore, we can say that $\frac{sinA}{a}=\frac{sinC}{c}$

We then plug in our given values to find C

$\frac{sin24}{77}=\frac{sinC}{162}$
$\frac{162*sin24}{77}=sinC$
Solving, we get 0.8557316387. We're not done yet!

We are trying to find an angle measure, so we'll do the inverse of the ratio we used (sin).

arcsin0.8557316387 (arcsin is the same as inverse sin)
=58.8 (approximate)

So the measure of angle C is 58.8. You could check this by reinserting it into the equation $\frac{sinA}{a}= \frac{sinB}{b} = \frac{sinC}{c}$ .

:)

6 0

3 years ago