Write an equation of the line passing through point P that is perpendicular to the given line.

Mathematics

2 answers:

cluponka [151]3 years ago

6 0

Answer:

y = 1/3x + 8

Step-by-step explanation:

1. Find slope of y = -3x+13

(m = -3)

2. Compute slope for perpendicular line

(m = 1/3)

basically, to find the perpendicular slope, you swap the numerator and denominator of your slope and swap it from negative to positive. (If you started with a positive slope it would turn negative)

3. Find the line with slope m=1/3 that passes through (6,0)

(y = 1/3x + 8)

katovenus [111]3 years ago

4 0

Answer:

y = 1/3x + 8

Step-by-step explanation:

*perpendicular means the reciprocal slope of the given line

m = 1/3

y = 1/3x + b

*plug in points with the point-slope equation

10 = 1/3(6) + b

10 = 2 + b

b = 8

*now plug everything into the equation

y = 1/3x + 8

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How to break down 4/5 + 13/15 = 1 2/3

nalin [4]

Answer:

Step-by-step explanation:

The left hand side of the equation contains proper fractions while the right hand side of the equation contains mixed fraction. The mixed fraction can be changed to improper fraction. 1 2/3 becomes 5/3

To breakdown the left hand side of the equation, we would take lowest common factor of 5 and 15. It is 15

Considering 4/5, if 15 divides 5,the result is 3. Multiplying 3 by 4 gives 12. So it becomes

12/15

Considering 13/15, if 15 divides 15,the result is 1, Multiplying 1 by 13 gives 13. So it becomes

13/15

The equation becomes

(12 + 13)/15 = 5/3

25/15 = 5/3

Simplifying 25/15 to its lowest terms, it becomes 5/3 so

5/3 = 5/3

6 0

3 years ago