3 years ago

Alec pours the same amount of soup into 3 bowls. He used 4 cups of soup. How much soup is in each bowl?

Mathematics

2 answers:

Gennadij [26K]3 years ago

7 0

4 cups / 3 bowls.....4/3 = 1.33 or 1 1/3 cups per bowl <==

Mrac [35]3 years ago

4 0

1 3/4 cups of soup per bowl

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Solve system using linear combination. 5x + 3y = 41 and 3x - 6y = 9 show all work.

SVETLANKA909090 [29]

Answer:

(7,2)

Step-by-step explanation:

5x + 3y = 41

3x - 6y = 9

Multiply the first equation by 2

2(5x + 3y) = 41 *2

10x +6y = 82

Add this to the second equation

10x +6y = 82

3x - 6y = 9

----------------------

13x = 91

Divide by 13

13x/13 = 91/13

x=7

Now we can find y

5x+3y = 41

5(7) +3y =51

35+3y=41

Subtract 35 from each side

35-35+3y=41-35

3y = 6

Divide by 3

3y/3 = 6/3

y=2

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OLEGan [10]

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2 years ago

Use the formula to evaluate the series 1/4 + 1/9 + 1/27 + 1/81.

Dmitriy789 [7]

Is the first term supposed to be 1/4, or did you actually mean 1/3?

I'll assume the latter. Write

$S=\dfrac13+\dfrac19+\dfrac1{27}+\dfrac1{81}$
$S=\dfrac13+\dfrac1{3^2}+\dfrac1{3^3}+\dfrac1{3^4}$
$\dfrac13S=\dfrac1{3^2}+\dfrac1{3^3}+\dfrac1{3^4}+\dfrac1{3^5}$
$\implies S-\dfrac13S=\dfrac13-\dfrac1{3^5}$
$\dfrac23S=\dfrac13\left(1-\dfrac1{3^4}\right)$
$S=\dfrac12\left(1-\dfrac1{81}\right)$
$S=\dfrac{40}{81}$