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3 years ago

Does anyone know how to factor this?

Mathematics

1 answer:

NNADVOKAT [17]3 years ago

6 0

3(4x-3)(x+6) is the answer

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Elena's hanging plant grew 6 inches in 4 months. At that rate, how many inches will it grow in 10 months

Oksi-84 [34.3K]

Answer:

The plant will grow 15 inches in 10 months.

Step-by-step explanation:

The given information is 6 inches = 4 months, and that may not sound like much but we can get the answer just from that tidbit.

Cross multiply :

$\frac{6 inches}{4 months}$ = $\frac{x}{10 months}$

4x = 60

Divide by 4 on both sides.

x = 15.

Therefore the plant will grow 15 inches in 10 months. Please mark brainliest! :)

5 0

2 years ago

How to make an equation with numbers 0.25, 7.00, and 27

shepuryov [24]

There are many ways to do this.

One way could be 0.25x+7.00=27

8 0

3 years ago

How are all angles in the 4th quadrant, negative or positive?

anastassius [24]

Answer:

They are all positive because you must go right.

They are all negative because you must go down.

Step-by-step explanation:

Example. (1,-4)

You go over one.

Down 4

5 0

3 years ago

Maya is the manager for the track team. She created a table to compare finish times from the second practice to the first

Oksi-84 [34.3K]

Answer:

Runners that decrease times are not improving

Step-by-step explanation:

4 0

3 years ago

Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)

Leni [432]

Alrighty

remember some rules
$(ab)^c=(a^c)(b^c)$
and
$x^{-m}=\frac{1}{x^m}$
and
$x^0=1$ for all real values of x
and
$(a^b)^c=a^{bc}$
and
$(\frac{a}{b})^c=\frac{a^c}{b^c}$
and
(a/b)/(c/d)=(ad)/(bc)
and
$(a^b)(a^c)=a^{b+c}$
and
$\frac{a^m}{a^n}=a^{m-n}$
and don't forget pemdas
example: $-x^m=-1(x^m)$ but $(-x)^m=(-1)^m(x^m)$

so

4.
$(\frac{c^{-2}}{2})^{-2}=$

$\frac{(c^{-2})^{-2}}{2^{-2}}=$

$\frac{c^4}{\frac{1}{2^2}}=$

$\frac{c^4}{\frac{1}{4}}=$

$4c^4$

5.

$\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=$

$\frac{(-1)^4(a)^4bc^5}{-1(a^2)(\frac{1}{b^3}(1)}=$

$\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=$

$\frac{(a^4bc^5)b^3}{(-1)(a^2)}=$

$\frac{-a^4b^4c^5}{a^2}=$

$-a^2b^4c^5$

3 0

3 years ago