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Eduardwww [97]
3 years ago
11

Evaluate P(4,4) Please help me with this asap. It is timed

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
7 0

Answer:

6 is the answer

:0 HOPE IT HELPED

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If <span>, which statement </span>must<span> be true?
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5 0
3 years ago
Angle sum theorem y=? Degrees
strojnjashka [21]

Answer:

2x + 70 = 110

x = 20

Step-by-step explanation:

180-110 = 70

70 + 20 + y = 180

y =90

4 0
3 years ago
To make two batches of nut bars jayda needs to use 4eggs. How many eggs are used in each batch of nut bars?
zloy xaker [14]
2 eggs
4÷2=2
happy to help
4 0
3 years ago
A car bought for $13,000 depreciates at a rate of 15% per year. Use an exponential function to find the value of the car after 5
anygoal [31]

<em>Answer:</em>

<em>$ 11093 </em>

<em>Explanation:</em><em> </em>

<em>Recall that the formula for compound interest is: </em>

<em> </em><em>A = P ( 1 + r/ n ) n ( t )</em><em>  </em>

<em>−−−−−−−−−−−−−−−−−−−−−−  </em>

<em> where: </em>

<em>A </em><em> =  future value </em>

<em>P</em><em>  =  principal (starting) amount </em>

<em>r</em><em>  =  annual interest rate, expressed as a decimal </em>

<em>n</em><em>  =  number of times the interest is compounded in a year </em>

<em>t</em><em>  =  number of years compound interest occurs for </em>

<em> </em>

<em>1 .</em><em> Start by substituting your known values into the formula. Note that the annual interest rate is  − 0.15  since the car depreciates (becomes lower in value) each year. </em>

<em> </em>

<em>A = 25000 ( 1 + − 0.15 1 ) 1 ( 5 )</em><em>  </em>

<em />

<em>2 .</em><em> Solve for  A . </em>

<em> </em>

<em>A = 25000 ( 0.85 ) )5 </em>

<em> A = 11092.63</em><em> </em>

<em> ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ </em>

<em>A ≈ $ 11093 a    </em>

<em>−−−−−−−−−−−−−−−</em>

3 0
3 years ago
Read 2 more answers
Find four consecutive integers such that the sum of the two largest subtracted from three times the sum of the two smallest is 7
serious [3.7K]

Answer:

18, 19, 20, 21

Step-by-step explanation:

Just like any of these problems, we should start by forming an equation for us to get a reference and plug in. We'll be using x as our variables.

As we have four consecutive integers (and not multiples) we can assume that the integers will be x, x+1, x+2, and x+3.

The sum of the two largest integers we have equals: n+2 + n+3 = 2n+5

and three times the sum of the two smallest = 3(n + n+1) = 6n+3

and the sum of t he two largest subtracted from three times the sum of the two smallest = (6n+3) - (2n+5) = 4n-2

4n-2=70

4n=68

n = 18.

n = 18, n+1 = 19, n+2 = 20, n+3 = 21

7 0
4 years ago
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