Area of the rectangular mat = 12 x 4 = 48 in²
Area of the 3 circles = 3( πr²) = 3(3.14 x 2²) = 37.68 in²
P(landing in a circle) = 37.68/48 = 157/200 = 0.79 (nearest hundredth)
Answer: The probability of landing in one of the circles is 0.79.
The correct answer would be C
Answer:
6
Step-by-step explanation:
You have 2 conditions.
1. The digits must be different.
2. The digits must add to 7.
There aren't very many
124
142
214
241
412
421
That's it. That's your answer. There are 6 of them
Uhh -1?
What’s the question?…
MY answer is #4 4.3 Times 107
