Step-by-step explanation:
so easy hahahahahah you are just a beginner
Answer:
x^2+2xy+y^2
Step-by-step explanation:
(x + y)(x + y)
FOIL
first x*x = x^2
Outer x*y = xy
inner: y*x = xy
last y*y = y^2
add together
x^2+xy+xy+y^2
Combine like terms
x^2+2xy+y^2
X intercept is when y=0
6x-2=0
x=1/3
x intercept is (1/3,0)
TADA
6 phone numbers are possible for one area code if the first four numbers are 202-1
<u>Solution:</u>
Given that, the first four numbers are 202-1, in that order, and the last three numbers are 1-7-8 in any order
We have to find how many phone numbers are possible for one area code.
The number of way “n” objects can be arranged is given as n!
Then, we have three places which changes, so we can change these 3 places in 3! ways

Hence 3! is found as follows:

So, we have 6 phone numbers possible for one area code.
44
Step-by-step explanation:
let boys be x and girls be y
x/y=5/6
x=5y/6....(1)
if 6 boys join the club that will be x+6
Therefore:
(x+6)/y=13/12
13y=12x+72
13y-12x=72
Recall x=5y/6
Therefore:
13y-12(5y/6)=72
13y-(2*5y)=72
13y-10y=72
3y=72
y=24 people
Therefore:
x=(5*24)/6
x=20 people
Therefore people in the club before are 20+24=44