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Tema [17]
3 years ago
6

Use the distributive property to factor the expression

Mathematics
1 answer:
Naily [24]3 years ago
5 0

Answer:

5(x^2 + 5)

Step-by-step explanation:

The binomial 5х^2 + 25 has the factor 5 in each term.  Thus, in factored form, 5х^2+ 25  = 5(x^2 + 5).

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Able has a younger sister and an older brother.
Vilka [71]

Answer:

5 years

Step-by-step explanation:

1. if able's age is x, then his sister's is x-4, and his brother's is 2x

2. if these sum to 32, then we can formulate the equation x+(x-4)+2x=32

3. now solve for x, 4x-4=32, 4x=36, x=9

4. if able's sister is x-4 years old, she is 9-4, or 5 years old

7 0
3 years ago
(adapted from Ross, 2.31) Three countries (the Land of Fire, the Land of Wind, and the Land of Earth) each make a 3 person team.
DaniilM [7]

Answer:

The answer is "\frac{2}{9} \  and \ \frac{1}{9}"

Step-by-step explanation:

In point a:

The requires  1 genin, 1 chunin , and 1 jonin to shape a complete team but we all recognize that each nation's team is comprised of 1 genin, 1 chunin, and 1 jonin.

They can now pick 1 genin from a certain matter of national with the value:

\frac{1}{\binom{3}{1}}=\frac{1}{3} .

They can pick 1 Chunin form of the matter of national with the value:

\frac{1}{\binom{3}{1}}=\frac{1}{3} .

They have the option to pick 1 join from of the country team with such a probability: \frac{1}{\binom{3}{1}}=\frac{1}{3}

And we can make the country teams: 3! = 6 different forms. Its chances of choosing a team full in the process described also are:

6 \times \frac{1}{3}\times \frac{1}{3}\times \frac{1}{3}=\frac{2}{9}.

In point b:

In this scenario, one of the 3 professional sides can either choose 3 genins or 3 chunines or 3 joniners. So, that we can form three groups that contain the same ninjas (either 3 genin or 3 chunin or 3 jonin).

Its likelihood that even a specific nation team ninja would be chosen is now: \frac{1}{\binom{3}{1}}=\frac{1}{3}

Its odds of choosing the same rank ninja in such a different country team are: \frac{1}{\binom{3}{1}}=\frac{1}{3}

The likelihood of choosing the same level Ninja from the residual matter of national is: \frac{1}{\binom{3}{1}}=\frac{1}{3} Therefore, all 3 selected ninjas are likely the same grade: 3\times \frac{1}{3}\times \frac{1}{3}\times \frac{1}{3}=\frac{1}{9}

4 0
3 years ago
Read 2 more answers
Since the card has $0 minimum payments for the first 4 years it is active, Emma wonders how much it will cost her if she
nikitadnepr [17]

Answer:

545

Step-by-step explanation

300(1.0125)^48 use this equation! Plato User!

7 0
3 years ago
1. (12 points) The tennis team at Taft High School has 8 players, and the tennis team at McKinley High School has 7 players. Reb
Marta_Voda [28]

Complete Question

1. (12 points) The tennis team at Taft High School has 8 players, and the tennis team at McKinley High School has 7 players. Rebecca is on the team at Taft, and her sister Leah is on the team at McKinley. The two teams are going to play a tournament with 4 rounds. In each round, one player from Taft will play a match against one player from McKinley. Each player can play in at most one match. A schedule for the tournament consists of an ordered list of the names of the players from each school who will play in each of the four rounds. The schedule does not include the results of each match.

(a) How many schedules are there?

(b) How many schedules include neither sister?

Answer:

a

   N  =  1,411,200

b

  M  =  302, 400

Step-by-step explanation:

From the question we are told that

   The  number of players in Taft High School is t =  8

    The  number of players in McKinley High School  is k = 7

   The number of rounds is  n  =  4

   The highest number of match each player can play is  w =  1

   

Generally the total number of schedules is  

      N  = ^tP_4 * ^k P_4

      N  = ^8P_4 * ^7 P_4

=>   N  =  \frac{8!}{(8-4)!} * \frac{7!}{(7-4)!}

=>   N  =  \frac{8!}{4!} * \frac{7!}{3!}

=>  N  =  \frac{8*7 *6*5*4*3*2*1}{4*3*2*1} * \frac{7*6*5*4*3*2*1}{3*2*1}

=>  N  =  1,411,200

Generally the  number of schedules that include neither of the sisters is  mathematically represented as

        M= \ ^{t-1}P_4 *\ ^ {k-1} P_4

        M= \ ^{8-1}P_4 *\ ^ {7-1} P_4

=>    M= \ ^{7}P_4 *\ ^ {6} P_4

=>     M  =  \frac{7!}{(7-4)!} * \frac{6!}{(6-4)!}

=>     M  =  \frac{7!}{3!} * \frac{6!}{2!}

=>     M  =  \frac{7 *6*5*4*3*2*1}{3*2*1} * \frac{6*5*4*3*2*1}{2*1}

=>      M  =  302, 400

8 0
3 years ago
What is square root of 250 form of 6
cupoosta [38]

30√10


HOPE THIS HELPS!!

4 0
4 years ago
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