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Alinara [238K]
4 years ago
15

Please PLEASE HELP me

Mathematics
2 answers:
Phantasy [73]4 years ago
6 0
It has to be the first one
SCORPION-xisa [38]4 years ago
4 0

Answer:

The answer is option 2.

Step-by-step explanation:

You can find it using Pythagoras Theorem' :

{c}^{2}  =  {a}^{2}  +  {b}^{2}

Let a be 15 units,

Let b be 14 units,

{c}^{2}  =  {15}^{2}  +  {14}^{2}

{c}^{2}  = 421

c =  \sqrt{421}

c = 20.5 \: units \: (3s.f)

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Hunter-Best [27]

Let's simplify the following expression:

\text{ }\frac{\text{ \lparen2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{\text{ 6x}^5\text{y}^{-4}\text{z}^{-5}}{\text{ \lparen2x}^6\text{y}^3\text{z}^{-3})^2}

We get,

\text{ }\frac{(\text{2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{  }\frac{6x^5y^{-4}z^{-5}}{(2x^6y^3z^{-3})^2}\text{ }\frac{(2x^4-y^6z^{-4})^2(6x^5y^{-4}z^{-5})}{(2x^2z^3)(2x^6y^3z^{-3})^2}\text{ }\frac{(4x^8\text{ - 4x}^4y^6z^{-4}\text{ + y}^{12}z^{-8})(6x^5y^{-4}z^{-5})}{(2x^2z^3)(4x^{12}y^6z^{-6})}\text{ }\frac{24x^{13}y^{-4}z^{-5}\text{ - 24x}^9y^2z^{-9}\text{ + 6x}^5y^8z^{-13}}{8x^{14}y^6z^{-3}}

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Step-by-step explanation:

Hopefully this helped, if not HMU and I will try my best to get you a better answer! :)

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Perimeter of a closed figure is the sum of length of its outline. The perimeter of the consider triangular pool is: 12x^2 + 8x + 25 units.

<h3>How to calculate perimeter of a triangular figure?</h3>

Perimeter of a triangle = Sum of lengths of all its 3 sides.

For the given case, we have:

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Thus, its perimeter is calculated as:

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The perimeter of the consider triangular pool is: 12x^2 + 8x + 25 units.

Learn more about perimeter here:

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