f(x) is a quadratic equation with the x-side squared and a is positive which means that the graph of the function is a parabola facing up. The range of f(x) is given by {y|y ≥ k}, where k is the y-coordinate of the vertex.

, written in vertex form is

, where (h, k) = (-1, -11)

Therefore, range ={y|y ≥ -11}

3 0

2 years ago

Show that one zero of 8x230x27 is the square of the other.

murzikaleks [220]

Answer:

8x2-30x+27 has one root (9/4) the square of the other (3/2)

Step-by-step explanation:

8x2+30x+27 = (2*x+3)*(4*x+9) => solution = {-3/2, -4/9}

One is not the square of the other because squares are positive.

8x2-30x+27 = (2*x-3)*(4*x-9) =>

solution = {3/2, 4/9} since (4/9 = (3/2)^2, therefore the preceding question is correct.

7 0

3 years ago

2 3/4 divided by 1/2 ?

Vladimir [108]

Answer:

5.5

Step-by-step explanation:

7 0

2 years ago

A n =−1+3(n−1) an=−1+3(n−1) what is the 55 term in the sequence

Sindrei [870]

ANSWER

$a_{55}=161$

EXPLANATION

The general term for the sequence is

$a_n=-1+3(n-1)$

To find the 55th term, we have to substitute
$n = 55$
in to the general term and simplify.

This implies that,

$a_{55}=-1+3(55-1)$

$a_{55}=-1+3(54)$

$a_{55}=-1+162$

$a_{55}=161$

Therefore the 55th term is 161.

8 0

2 years ago