False. Perpendicular lines run beside each other not through each other.
C. 0.50.
I believe that is the answer. Hope this helped! Sorry if I’m wrong.
-Bella :)
Be:
Number of hours: n
<span>The cost of renting a bike for the first hour is $7:
n=1→f(n)=f(1)=$7
</span>He is charged $2.50 for every additional hour of renting the bike:
f(n)=f(n-1)+2.50, for <span>n ≥ 2
</span>
f(1)=7; f(n)=f(n-1)+2.50, for <span>n ≥ 2 (sixth option)
</span>
f(n)=f(1)+2.50(n-1)
f(n)=7+2.50(n-1)
f(n)=7+2.50n-2.50
f(n)=2.50n+4.50 (fifth option)
Answers:
Fifth option: f(n)=2.50n+4.50, and
Sixth option: f(1)=7; f(n)=f(n-1)+2.50, for <span>n ≥ 2</span>
Answer:
<em>H</em>₀: <em>μ₁ = μ₂= μ₃</em>
<em>Hₐ: </em>At least one of the means is different.
Step-by-step explanation:
Analysis of variance or ANOVA test is used to determine whether the means of different groups are similar or not.
The hypothesis of an ANOVA test for <em>n</em> homogeneous groups is:

In this case the researcher is testing whether the mean bone mineral density is different for the three different groups.
The hypothesis for this test can be defined as follows:
<em>H</em>₀: The mean bone mineral density is not different for the three different groups, i.e. <em>μ₁ = μ₂= μ₃</em>
<em>Hₐ: </em>The mean bone mineral density is different for the three different groups, i.e. at least one of the means is different.