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romanna [79]
3 years ago
13

12) A basketball player attempts eight free

Mathematics
1 answer:
Alenkasestr [34]3 years ago
4 0

Answer:

where is the rest of the question?

Step-by-step explanation:

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One teacher wants to give each student 2/3 of a slice of pizza . If the teacher has 4 slices of pizza how many students will rec
Deffense [45]

Answer: 6 students

Step-by-step explanation:

The teacher wants to give each student 2/3 of a slice of pizza but only has 4 slices to give.

If each student gets 2/3 out of 4 slices, the number of students receiving will be:

= Slices / proportion per slice

= 4 / 2/3

= 4 * 3/2

= 12/2

= 6 students

5 0
3 years ago
Which of the following is in order from least to greatest
vovangra [49]
The third option is ordered least to greatest
4 0
2 years ago
Yuson used her calculator to solve the equation 4/5x - 8 = 3. She entered the following on her screen and got an incorrect answe
Firlakuza [10]

Answer:

55/4

Explanation:

Let's solve your equation step-by-step.

4 /5x−8=3

Step 1: Add 8 to both sides.

4 /5x−8+8=3+8

4 /5 x = 11

Step 2: Multiply both sides by 5/4.

( 5 /4 )*( 4 /5 x)=( 5 /4 )*(11)

x=  55/4

Answer:

x=

55 /4

Hope that helps :)

 

4 0
3 years ago
Read 2 more answers
Ralph is making orange juice.
devlian [24]
D. 24 oz because 1cup is equal to 8 fluid ounces so in order to make 3 cups you have to multiply 3 by 8 which equals to 24
6 0
2 years ago
(a) Find parametric equations for the line through (1, 4, 4) that is perpendicular to the plane x − y + 2z = 7. (Use the paramet
Alex777 [14]

Answer:

x=1+t\\y=4-t\\z=4+2t

Step-by-step explanation:

A vector perpendicular to the plane ax+by+cz+d=0 is of the form (a,b,c).

So, a vector perpendicular to the plane x − y + 2z = 7 is (1,-1,2).

The parametric equations of a line through the point (x_0,y_0,z_0) and parallel to the vector (a,b,c) are as follows:

x=x_0+at\\y=y_0+bt\\z=z_0+ct

Put (x_0,y_0,z_0)=(1,4,4) and (a,b,c)=(1,-1,2)

Therefore,

x=1+t\\y=4-t\\z=4+2t

xy-plane:

Put z = 0 ⇒ t = -2 ⇒x = - 1 , y = 6

So, at point (-1,6,0)

yz-plane:

Put x = 0 ⇒ t = -1 ⇒ y = 5, z =2

So, at point (0,5,2)

xz-plane:

Put y = 0 ⇒ t = 4 ⇒ x = 5, z = 12

So, at point (5,0,12)

5 0
3 years ago
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