Answer:
1 is correct, 100.
2 is 500, not 470. since we're rounding to the nearest hundred, we would look at the tens place and if it's higher than 5 then round up.
3 is correct.
4 is correct.
5 is correct.
6 is correct.
7 is correct.
8 is 290, not 300. like i said before, but in this case we're rounding t the nearest ten instead of hundred. but the same rules apply.
9 is correct.
and 10 is correct!
i think that you did pretty well on most of these, but remember the rounding rule.
The answer is 14 beachside every 10 hours trained, you get an extra 100 dollars.
(a) By the fundamental theorem of calculus,
<em>v(t)</em> = <em>v(0)</em> + ∫₀ᵗ <em>a(u)</em> d<em>u</em>
The particle starts at rest, so <em>v(0)</em> = 0. Computing the integral gives
<em>v(t)</em> = [2/3 <em>u</em> ³ + 2<em>u</em> ²]₀ᵗ = 2/3 <em>t</em> ³ + 2<em>t</em> ²
(b) Use the FTC again, but this time you want the distance, which means you need to integrate the <u>speed</u> of the particle, i.e. the absolute value of <em>v(t)</em>. Fortunately, for <em>t</em> ≥ 0, we have <em>v(t)</em> ≥ 0 and |<em>v(t)</em> | = <em>v(t)</em>, so speed is governed by the same function. Taking the starting point to be the origin, after 8 seconds the particle travels a distance of
∫₀⁸ <em>v(u)</em> d<em>u</em> = ∫₀⁸ (2/3 <em>u</em> ³ + 2<em>u</em> ²) d<em>u</em> = [1/6 <em>u</em> ⁴ + 2/3 <em>u</em> ³]₀⁸ = 1024
