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MrMuchimi
3 years ago
15

What is the square root of -169

Mathematics
2 answers:
dezoksy [38]3 years ago
8 0
Square root -169
=  \sqrt{-169} =  \sqrt{169} * \sqrt{-1}
                          =   13*i  = 13i.

Note square root of -1 is represented by i.

Square roots usually have two answers;  +/-
More correct answer =  +/- 13i
aleksklad [387]3 years ago
6 0
\sqrt{-169} \to \boxed{ -  /+ 13i}
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4 years ago
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Which are the roots of the quadratic function f(q) = q^2 - 125? Select two options.
liubo4ka [24]

Answer:

None of the options are correct

Step-by-step explanation:

Given

f(q) = q^2 - 125

Required

The roots of the function

Since the function is a quadratic function; to get the roots of the function, f(q) must be equal to 0

f(q) = q^2 - 125 becomes

0 = q^2 - 125

Make q^2 the subject of formula

125= q^2

Rearrange

q^2 = 125

Take square roots of both sides

\sqrt{q^2}  = \sqrt{125}

q  = \sqrt{125}

Expand the square root of 125

q  = \sqrt{25 * 5}

q  = \sqrt{25} * \sqrt{5}

q = ±5 * \sqrt{5}

Split into 2

q  = 5 * \sqrt{5} or q  = -5 * \sqrt{5}

q  = 5  \sqrt{5} or q  = -5 \sqrt{5}

Hence, the roots of the quadratic function are q  = 5  \sqrt{5} or q  = -5 \sqrt{5}

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kkurt [141]

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Step-by-step explanation:

using y-y1/ x- x1=m

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3y-4x=9

8 0
3 years ago
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