Answer:
see explanation
Step-by-step explanation:
Given that y varies inversely as x then the equation relating them is
y = ← k is the constant of variation
To find k use the condition x = 2.5 when y = 100
k = yx = 100 × 2.5 = 250
y = ← equation of variation
Answer:
95.86% probability that the sample proportion will differ from the population proportion by less than 3%
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
For a proportion, we have that:
What is the probability that the sample proportion will differ from the population proportion by less than 3%
This is the pvalue of Z when X = 0.07 + 0.03 = 0.1 subtracted by the pvalue of Z when X = 0.07 - 0.03 = 0.04. So
X = 0.1
has a pvalue of 0.9793
X = 0.04
has a pvalue of 0.0207
0.9793 - 0.0207 = 0.9586
95.86% probability that the sample proportion will differ from the population proportion by less than 3%
Answer:
Window. Thank you so much.
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
Rather than picking, let's try to construct one from the description.
reflected over the x axis means -
the vertex is usually at (0,0), now how do we move a graph? or in other words translating it.
To move left and right you use where if you subtract h you move right and if you add h you move left. we go from (0,0) to (-4,2). so 0 to -4 is 4 left, so that means we add 4.
To move up and down we use Here if v is positive you move up and if v is negative you move down. going from (0,0) to (-4,2) it moves up 2
So now we put them all together And if you look, C matches that exactly.
<h2>For the number 1<u>.</u><u>.</u></h2>
<h2><u>angle </u><u>at </u><u>center </u><u>=</u><u> </u><u>2</u><u>×</u><u>a</u><u>n</u><u>g</u><u>l</u><u>e</u><u> </u><u>at </u><u>circumference</u></h2><h2><u>the </u><u>angle </u><u>at </u><u>center </u><u>(</u><u>o)</u><u> </u><u>is </u><u>equal</u><u> </u><u>to</u><u> </u><u>1</u><u>4</u><u>1</u></h2>
<u>therefore:</u>
<h2><u>1</u><u>4</u><u>1</u><u> </u><u>=</u><u> </u><u>2</u><u>x</u></h2><h2><u>divide</u><u> </u><u>both </u><u>sides </u><u>by </u><u>2</u></h2><h2><u>x </u><u>=</u><u> </u><u>7</u><u>0</u><u>.</u><u>5</u></h2>
<u>option</u><u> </u><u>(</u><u>A)</u><u>.</u>
<u>(</u><u> </u><u>the </u><u>number </u><u>2</u><u> </u><u>and </u><u>3</u><u> </u><u>questions</u><u> </u><u>aren't</u><u> </u><u>correct </u><u>)</u>