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labwork [276]
3 years ago
7

2abc-3ab if a=2, b=-3, c=2

Mathematics
1 answer:
Elden [556K]3 years ago
5 0
So a=2 since a is next to the first 2 it would be 2x2 which equals 4 next it’s B and B= -3 so -3x4 equals -12 and then c also equals 2 so it would be -12x2 and that equals -24. Moving on to the next part as I said a=2 so it would be 3x2 and that equals 6 next it’s B again so 6x -3 equals -18 so now take -24 and -18 and subtract them and you would get -6. Sorry if this answer is wrong I did my best...hope it helped.
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B because it rounds
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I need help plzz What is m 50*<br> 35*<br> 130*<br> 95*
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If you run 4 1/2 miles in three quarter of an hour, how many miles would you run in two thirds
olga_2 [115]

Answer:4

Step-by-step explanation: each quarter of an hour is 1.5 miles they both can go into 12 so if you multiply 2*4 and 3*4 you get 8/12 and if you multiply 3*3 and 4*3 you get 9/12 then you subtract 9/12 by 8/12 to get so 1/12=1/2 miles so you would subtract 4 1/2 by 1/2 to get 4

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2 years ago
Please help me with this question :)​
klio [65]

Answer:

y>5/6

Step-by-step explanation:

5y+3>-7y+13

5y+7y>13-3

12y/12>10/12

y>5/6

This is an inequality, which shows where the variable y does or does not exist

from this we can say

y: (-infinity,5/6) (5/6, infinity]

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3 0
2 years ago
Find the perimeter of pentagon STUVW WITH VERTICES S(0,0) T(3,-2) U(2,-5) V(-2,-5) W(-3,-2)
andrew11 [14]
Use the distance formula.

\sqrt{( x_{2} - x_{1} )^2 + (y_{2} - y_{1})^2}

 
Points S and W.
\sqrt{(3)^2 + (2)^2}

\sqrt{9+4}

\sqrt{13}

~3.6

Points S and T
\sqrt{(3 - 0)^2 + (-2 - 0)^2}

\sqrt{(3)^2 + (-2)^2}

\sqrt{9+4}

\sqrt{13}

~3.6

Points T and U
\sqrt{(3 - 2)^2 + (-2 + 5)^2}

\sqrt{(1)^2 + (3)^2}

\sqrt{1+9}

\sqrt{10}

~3.1

Points U and V
\sqrt{(2+2)^2 + (-5 + 5)^2}

\sqrt{(4)^2 + (0)^2}

\sqrt{16}

~4

Points V and W
\sqrt{(-2+3)^2 + (-5 + 2)^2}

\sqrt{(1)^2 + (-3)^2}

\sqrt{2+9}

\sqrt{11}

~3.3

Add all these together.

3.3 + 3.1 + 4 + 3.1 + 3.6
≈17
4 0
3 years ago
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