Length= 40cm
Breadth= 22cm
Perimeter of the rectangle= Length of the wire
=2(l+b)= 2(40cm + 22cm)
=2\times62cm = 124cm
Now, the wire is rebent into a square.
Perimeter= 124cm
4\times side=124
Therefore side= \frac{124}{4}cm= 31cm
So, the measure of each side= 31cm
Area of rectangular shape= l\times b
=40cm\times22cm
=880cm^2
Area of a square shape= \left(Side\right)^2
=\left(31\right)^2=961cm^2
Since 961cm^2\ >\ 880cm^2
Hence, the square encloses more area.
Answer:
what i need to find there
Step-by-step explanation:
i only find y like an expression
Isolate the variable by dividing each side by factors that don't contain the variable.
y=sin(30t2hea+90)/2+1/16
First bring all the x's to one side.
then subtract them.
then divide 24 by 3 to get the x alone and get your answer.
11x-8x=24
3x=24
x=8
Answer:
Step-by-step explanation:
Let angle ABZ be angle 1 and angle ZBC be angle 2.
Angle 1 = 85 degree
Angle 2 = 6x + 9
measure of angle ABC = 24x+4
Angle 2 = ABC - 85
6x + 9 = 24x + 4 - 85
6x - 24x = 4 - 85 - 9
-18x = -90
x = -90/-18 = 90/18 =
x = 5
Therefore the measure of angle 2 = 6*5 + 9 = 30+9 = 39 degree
Therefore the measure of angle ZBC = 39 degree
Hope you understand
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