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tatuchka [14]
3 years ago
10

Find an equation of the line that has the given slope and contains the given point. m=7/3 (1,6)

Mathematics
1 answer:
iris [78.8K]3 years ago
5 0

The point-slope form:

y-y_1=m(x-x_1)

We have the point (1, 6) and the slope m = 7/3. Substitute:

y-6=\dfrac{7}{3}(x-1)      <em>use distributive property</em>

y-6=\dfrac{7}{3}x-\dfrac{7}{3}          <em>add 6 to both sides</em>

y=\dfrac{7}{3}x+\dfrac{11}{3}        <em>multiply both sides by 3</em>

3y=7x+11           <em>subtract 7x from both sides</em>

-7x+3y=11         <em>change the signs</em>

7x-3y=-11

Answer:

point-slope form: y-6=\dfrac{7}{3}(x-1)

slope-intercept form: y=\dfrac{7}{3}x+\dfrac{11}{3}

standard form: 7x-3y=-11

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<em><u>Answer:</u></em>

4 or 7 (Check the explanation to see which one your equation <em>actually</em> is.

<em><u>Step-by-step explanation:</u></em>

One thing I want to clarify for you, It's Evaluate, not Avaluate.

Okay so, we want to find the value of 2^3x-1 and we know x = 1.

You didn't really clarify if the expression was 2^{3x-1} or 2^{3x}-1, so I'll be doing both:

For 2^{3x-1}, we should plug in x to get 2^{3(1)-1} and then simplify to get 2^{2}.

2 to the power of 2 or 2^{2} is equal to 2 * 2 or 4.

The second one, 2^{3x}-1, we should plug in x to get 2^{3(1)}-1 and then to become 2^{3}-1. 2 to the power of 3 or 2^{3} is 8 and then minus 1 is 7.

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Step-by-step explanation:

always remember, equations and inequalities are like a scale with 2 pans (left and right).

a variable is like a placeholder, an empty spot on the pans. and the expressions on both sides are kind of the conditions for the things to put in these empty spots so that the status of the scale stays unchanged.

for an equation the scale has to stay balanced all the time.

and in an inequality one side is heavier that the other (it normally does not matter how much heavier) with "<" or ">" signs, or the scale can be also balanced with "<=" or ">=" signs. just the other side must never be heavier.

A

so, in our case here

2x - 5 = 3

yes, the solution (the ONLY solution, actually) is x = 4. no other value of x allows the scale to be balanced.

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well, since it is a ">=" sign, we can be lazy and treat it like the equation above, and x = 4 is therefore a valid solution for the inequality too.

but so is every other value of x that makes the left side "heavier". what about e.g. 5 ?

2×5 - 5 >= 3

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true, great ! so, e.g. x = 5 is also a valid solution.

what else ?

let's simplify the inequality

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so, really every value of x that is greater or equal to 4 is a valid solution for the inequality.

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-2x - 5 = 3

yes, the solution (the ONLY solution, actually) is x = -4. no other value of x allows the scale to be balanced.

-2x - 5 >= 3

well, since it is a ">=" sign, we can be lazy and treat it like the equation above, and x = -4 is therefore a valid solution for the inequality too.

but so is every other value of x that makes the left side "heavier". what about e.g. -5 ?

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remember, -×- = +

10 - 5 >= 3

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true, great ! so, e.g. x = -5 is also a valid solution.

what else ?

let's simplify the inequality

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