All categories

3 years ago

APML - ATAQ. Solve for x and QR HELP ASAP!!!!! PLZZZZZ

Mathematics

1 answer:

Roman55 [17]3 years ago

7 0

Answer:

x = 7

Step-by-step explanation:

(7x-9)(2x+2) = 35/14

98x - 126 = 70x + 70

28x = 196

x = 7

You might be interested in

Someone plz help me giving brainliest!

Arada [10]

Answer:

the estimate is : 39 7/32

the answer is : 46 9/35

4 0

3 years ago

Suiting at 6 a.m., cars, buses, and motorcycles arrive at a highway loll booth according to independent Poisson processes. Cars

dem82 [27]

Answer:

Step-by-step explanation:

From the information given:

the rate of the cars = $\dfrac{1}{5} \ car / min = 0.2 \ car /min$

the rate of the buses = $\dfrac{1}{10} \ bus / min = 0.1 \ bus /min$

the rate of motorcycle = $\dfrac{1}{30} \ motorcycle / min = 0.0333 \ motorcycle /min$

The probability of any event at a given time t can be expressed as:

$P(event \ (x) \ in \ time \ (t)\ min) = \dfrac{e^{-rate \times t}\times (rate \times t)^x}{x!}$

∴

(a)

$P(2 \ car \ in \ 20 \ min) = \dfrac{e^{-0.20\times 20}\times (0.2 \times 20)^2}{2!}$

$P(2 \ car \ in \ 20 \ min) =0.1465$

$P ( 1 \ motorcycle \ in \ 20 \ min) = \dfrac{e^{-0.0333\times 20}\times (0.0333 \times 20)^1}{1!}$

$P ( 1 \ motorcycle \ in \ 20 \ min) = 0.3422$

$P ( 0 \ buses \ in \ 20 \ min) = \dfrac{e^{-0.1\times 20}\times (0.1 \times 20)^0}{0!}$

$P ( 0 \ buses \ in \ 20 \ min) = 0.1353$

Thus;

P(exactly 2 cars, 1 motorcycle in 20 minutes) = 0.1465 × 0.3422 × 0.1353

P(exactly 2 cars, 1 motorcycle in 20 minutes) = 0.0068

(b)

the rate of the total vehicles = 0.2 + 0.1 + 0.0333 = 0.3333

the rate of vehicles with exact change = rate of total vehicles × P(exact change)

$= 0.3333 \times \dfrac{1}{4}$

= 0.0833

∴

$P(zero \ exact \ change \ in \ 10 minutes) = \dfrac{e^{-0.0833\times 10}\times (0.0833 \times 10)^0}{0!}$

P(zero exact change in 10 minutes) = 0.4347

The probability of the 7th motorcycle after the arrival of the third motorcycle is:

$P( 4 \ motorcyles \ in \ 45 \ minutes) =\dfrac{e^{-0.0333\times 45}\times (0.0333 \times 45)^4}{4!}$

$P( 4 \ motorcyles \ in \ 45 \ minutes) =0.0469$

Thus; the probability of the 7th motorcycle after the arrival of the third one is = 0.0469

P(at least one other vehicle arrives between 3rd and 4th car arrival)

= 1 - P(no other vehicle arrives between 3rd and 4th car arrival)

The 3rd car arrives at 15 minutes

The 4th car arrives at 20 minutes

The interval between the two = 5 minutes

For Bus:

P(no other vehicle other vehicle arrives within 5 minutes is)

= $\dfrac{6}{12} = 0.5$

For motorcycle:

$= \dfrac{2 }{12} = \dfrac{1 }{6}$

∴

The required probability = $1 - \Bigg ( \dfrac{e^{-0.5 \times 0.5^0}}{0!} \times \dfrac{e^{-1/6}\times (1/6)^0}{0!} \Bigg)$

= 1- 0.5134

= 0.4866

6 0

3 years ago

What is tan theta when csc theta =2 sqrt 3?

Slav-nsk [51]

Answer:

$\displaystyle \tan\theta=\frac{\sqrt{11}}{11}$

Step-by-step explanation:

Trigonometric Identities

If the trigonometric function value of an angle is given, we can find the rest of the trigonometric values of the angle by using one or more of the fundamental identities.

To solve this problem, we need to use the following identities:

$\displaystyle \cot^2\theta=\csc^2\theta-1$

$\displaystyle \tan\theta=\frac{1}{\cot\theta}$

Since we are given:

$\displaystyle \csc\theta=2\sqrt{3}$

And the angle is in the first quadrant, calculate the cotangent:

$\displaystyle \cot^2\theta=(2\sqrt{3})^2-1$

$\displaystyle \cot^2\theta=4*3-1=11$

$\displaystyle \cot\theta=\sqrt{11}$

The tangent is:

$\displaystyle \tan\theta=\frac{1}{\sqrt{11}}$

Rationalizing the denominator:

$\displaystyle \tan\theta=\frac{1}{\sqrt{11}}*\frac{\sqrt{11}}{\sqrt{11}}$

$\boxed{\displaystyle \tan\theta=\frac{\sqrt{11}}{11}}$

7 0

3 years ago

Please help with this

12345 [234]

1. 5
2. 8
3. 24
4. 45
I don't know if this was right but it should be bc it shows you all ready for a and b and then for 3 you just times 8 by 3 and for 4 you times that by 9×5

8 0

3 years ago

Which polynomial is factored completely?

larisa [96]

Answer: fourth answer

Step-by-step explanation:

you cant factor it

3 0

2 years ago