Answer:
T=138 °C
Explanation:
Given that
m = 0.028 kg
Net work output W= 60 KJ
T₂=2T₁
As we know that efficiency of Carnot heat engine given as
η = 0.5
We know that
Qa=heat addition
W= net work output
Qa= 120 KJ
From first law
Qa= W+ Qr
Qr= 120 - 60
Qr= 60 KJ
Qr Is the heat rejection.
Heat rejection per unit mass
Qr=60 / 0.028 = 2142.85 KJ/kg
Qr= 2142.85 KJ/kg
Temperature at which latent heat of steam is 2142.85 KJ/kg will be our answer.
T=138 °C
The temperature corresponding to 2142.85 KJ/kg will be 138 °C.
T=138 °C
Answer:
Check the 2nd, 3rd and 4th statements.
Explanation:
Answer:
b) Endothermic Chemical Reactions in a solid
Explanation:
Endothermic reactions consume energy, which will result in a cooler solid when the reaction finishes.
Answer:
The lift coefficient is 0.3192 while that of the moment about the leading edge is-0.1306.
Explanation:
The Upper Surface Cp is given as
The Lower Surface Cp is given as
The difference of the Cp over the airfoil is given as
Now the Lift Coefficient is given as
Now the coefficient of moment about the leading edge is given as
So the lift coefficient is 0.3192 while that of the moment about the leading edge is-0.1306.
