Answer:
Relative density = 0.545
Degree of saturation = 24.77%
Explanation:
Data provided in the question:
Water content, w = 5%
Bulk unit weight = 18.0 kN/m³
Void ratio in the densest state,
= 0.51
Void ratio in the loosest state,
= 0.87
Now,
Dry density, 

= 17.14 kN/m³
Also,

here, G = Specific gravity = 2.7 for sand

or
e = 0.545
Relative density = 
= 
= 0.902
Also,
Se = wG
here,
S is the degree of saturation
therefore,
S(0.545) = (0.05)()2.7
or
S = 0.2477
or
S = 0.2477 × 100% = 24.77%
1.Ross fixes a dishwasher for a homeowner.
3.Cassandra fixes holes in an old road.
Explanation:
Note: Refer the diagram below
Obtaining data from property tables
State 1:

State 2:

State 3:

State 4:
Throttling process 
(a)
Magnitude of compressor power input


(b)
Refrigerator capacity



(c)
Cop:


Answer:
Heat gain of 142 kJ
Explanation:
We can see that job done by compressing the He gas is negative, it means that the sign convention we are going to use is negative for all the work done by the gas and positive for all the job done to the gas. With that being said, the first law of thermodynamics equation will help us to solve this problem.
Δ
⇒
Δ

Therefore, the gas gained heat by an amount of 142 kJ.