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kkurt [141]
3 years ago
10

While reflecting on the solutions and the process of concept generation, the development team takes a look at some critical ques

tions such as:________.
1. Is the team developing confidence that the solution space has been fully explored?
2. Are there alternative diagrams and alternative ways to decompose the problem?
3. Have external sources been thoroughly pursued, and everyone’s ideas been accepted and integrated in the process?
4. All of the above
Engineering
1 answer:
hammer [34]3 years ago
5 0

Answer:

While reflecting on the solutions and the process of concept generation, the development team takes a look at some critical questions such as:________.

4. All of the above

Explanation:

The team must explore its solution space, including some external sources. Then, it must integrate its findings with the ideas of team members, ensuring the consideration of all possible ways to decompose the problem. This is because employing a structured process to concept generation enables the team to come up with creative solutions to design concepts.

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NASA SPACE SHUTTLE QUESTION:
vfiekz [6]

Explanation:

The Challenger accident made them aware of the risks. They had been a little naive, since it was never believed that such a thing could happen. This, together with Space Shuttle Columbia disaster revealed the risks of the space shuttle program, which also had very high maintenance costs.

8 0
3 years ago
True or False: Drag and tailwind are examples of a contact force.<br> tyy guyss
zloy xaker [14]

Answer:

False

Explanation:

8 0
3 years ago
In a right triangle, the square of the length of one side is equal to the sum of the squares of the lengths of the other two sid
Dovator [93]

Answer:

C++ code is explained below

Explanation:

/Remove the following line

//if not using visual studio.

#include "stdafx.h"

//Import the required header files.

#include <iostream>

using namespace std;

//Define the main function.

int main(void)

{

    //Define the variables.

    double side1, side2, side3;

    //Prompt the user to enter the sides of the triangle.

    cout << "Enter the side of the triangle:" << endl;

    cout << "Enter first side of triangle:" << endl;

    cin >> side1;

    cout << "Enter second side of triangle:" << endl;

    cin >> side2;

    cout << "Enter third side of triangle:" << endl;

    cin >> side3;

    cout << endl;

    //Check if the triangle sides are valid

    if ((side1 + side2 > side3) &&

         (side1 + side3 > side2) &&

         (side2 + side3 > side1))

    {

         //Check the condition for right angle triangle

         if ((side3*side3 == (side1*side1 + side2*side2)) ||

             (side2*side2 == (side3*side3 + side1*side1)) ||

             (side1*side1 == (side3*side3 + side2*side2)))

//Display that the triangle is right-angled triangle.

             cout << "It is a right-angled triangle." << endl;

         else

//Display that the triangle is not the right-//angled triangle.

             cout << "It is not a right-angled triangle."

<< endl;

    }

    else

         //Display not the valid side.

         cout << "Not a valid side." << endl;

    //Remove the following line if

    //not using visual studio.

    system("pause");

    return 0;

}

8 0
3 years ago
The fan blades suddenly experience an angular acceleration of 2 rad/s2. If the blades are rotating with an initial angular veloc
madreJ [45]

Answer:

Option B

116 ft/s^{2}

Explanation:

\theta=2 rev=2(2\pi)=4\pi

\alpha \theta=0.5(\omega_f^{2}-\omega_i^{2})

\alpha (4\pi)= 0.5(\omega_f^{2}-\omega_i^{2})

\alpha (8\pi)= (\omega_f^{2}-\omega_i^{2})

(2) (8\pi)= (\omega_f^{2}-\omega_i^{2})

(2) (8\pi)= (\omega_f^{2}-4^{2})

\omega_f=8.14 rads/s

v=r\omega=1.75*8.14=14.245 ft/s

Centripetal acceleration =\omega_f^{2} r=8.14^{2}*1.75=115.95 ft/s^{2}

Tangential component=dr=2*1.75=3.5

Resultant=\sqrt{3.5^{2}+115.95^{2}}\approx 116 ft/s^{2}

5 0
3 years ago
A 179 ‑turn circular coil of radius 3.95 cm and negligible resistance is immersed in a uniform magnetic field that is perpendicu
suter [353]

Answer:

The energy, that is dissipated in the resistor during this time interval is 153.6 mJ

Explanation:

Given;

number of turns, N = 179

radius of the circular coil, r = 3.95 cm = 0.0395 m

resistance, R = 10.1 Ω

time, t = 0.163 s

magnetic field strength, B = 0.573 T

Induced emf is given as;

emf= N\frac{d \phi}{dt}

where;

ΔФ is change in magnetic flux

ΔФ  = BA = B x πr²

ΔФ  = 0.573 x π(0.0395)² = 0.002809 T.m²

emf = N\frac{d \phi}{dt} = 179(\frac{0.002809}{0.163} ) = 3.0848 \ V

According to ohm's law;

V = IR

I = V / R

I = 3.0848 / 10.1

I = 0.3054 A

Energy = I²Rt

Energy = (0.3054)² x 10.1 x 0.163

Energy = 0.1536 J

Energy = 153.6 mJ

Therefore, the energy, that is dissipated in the resistor during this time interval is 153.6 mJ

6 0
3 years ago
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