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Serggg [28]
3 years ago
5

Sheila is running in a race that is 5 kilometers long . After 10 minutes , she has run 1.875 kilometers . How much father does s

heila have to run to finsh the race
Mathematics
1 answer:
navik [9.2K]3 years ago
4 0

Answer: 3.125\ kilometers

Step-by-step explanation:

In order to solve this exercise you need to analize the information provided.

Notice that , according to the exercise, Sheila has to run a total of 5 kilometers to finish the race.

You know that the distance Sheila has run in 10 minutes is 1.875 kilometers.

Then, knowing the above, you need to subtract the total lenght of the race (5 kilometers) and the distance she has already run (1.875 kilometers) in order to calculate how much farther Sheila has to run to finish the race.

Therefore, you get the following result:

5\ kilometeres-1.875\ kilometers=3.125\ kilometers

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Montano1993 [528]
Recall your d = rt.

so hmm is about the same as the other one... so say the boat has a speed rate of "b", well, going downstream the boat goes say " b + 2 ", because the current is adding to it, and going upstream is " b - 2 " because the current is eroding from it.

So if the whole trip took 14 hours, say it took "t" hours going upstream, then going downstream it took the slack or " 14 - t ".

Also notice, the trip forth and back is the same 45 miles.

\bf \begin{array}{lccclll}
&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
Upstream&45&b-2&t\\
Downstream&45&b+2&14-t
\end{array}
\\\\\\
\begin{cases}
45=t(b-2)\implies \frac{45}{b-2}=\boxed{t}\\\\
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----------\\
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\\\\\\
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\\\\\\
0=14b^2-90b-56\implies 0=7b^2-45b-28
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-\frac{4}{7}\\\\
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anzhelika [568]

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<h3>How to Interpret Graph of Asymptotes Functions?</h3>

From the given graph , the vertical asymptote is at x = 4

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To find out vertical asymptote we set the denominator = 0

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vitfil [10]

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Given : if point A is reflected over the y axis and its original location was (2,3).

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Solution : We have given that point ( 2, 3)

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Here only the x coordinate will change .

Then , point A ( 2, 3) →→ ( -2 , 3)

Therefore,  point A ( 2, 3) →→ ( -2 , 3)

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