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raketka [301]
2 years ago
7

Which shows the graph of the solution set of y < 1/3 x – 2?

Mathematics
2 answers:
AnnZ [28]2 years ago
6 0

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

y< \frac{1}{3}x-2

The solution of the inequality is the shaded area below the dashed line

The equation of the line is y= \frac{1}{3}x-2

The slope of the line is positive m= \frac{1}{3}

The y-intercept of the line is the point (0,-2)

The x-intercept of the line is the point (6,0)

so

The graph in the attached figure

Readme [11.4K]2 years ago
5 0
y < \dfrac{1}{3}x-2\\\\y=\dfrac{1}{3}x-2\\\\for\ x=0\to y=\dfrac{1}{3}\cdot0-2=-2\to(0;-2)\\\\for\ x=6\to y=\dfrac{1}{3}\cdot6-2=2-2=0\to(6;\ 0)



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Please solve for n the following equation..............-2 = -n + 8
Zielflug [23.3K]

Answer:

n=-5

Step-by-step explanation:

4 0
3 years ago
The infinite sequence 1, 6, 15, 28, 45, ... exhibits which pattern? multiply the term number by 2, subtract 1 from the result, m
Amanda [17]
The correct response is ;
<span>multiply the term number by 2, subtract 1 from the result, multiply by 2 times the term number, and divide the result by 2.
if term number is x,
the number in the pattern for xth term is ;
multiply term number by 2 - 2x
subtract 1 - 2x - 1
multiply by 2 times the term number - (2x-1) * 2x
divide by 2 - (</span>(2x-1) * 2x)/2
so first term x=1
((2*1-1) * 2*1)/2
2/2 = 1
second term x = 2
((2*2-1) * 2*2)/2
(3*4)/2 = 6
third term x = 3
((2*3-1) * 2*3)/2
5*6/2 = 15
fourth term  x= 4
((2*4-1) * 2*4)/2
56/2 = 28
Therefore the above response shows the correct pattern
5 0
3 years ago
Read 2 more answers
Independent Practice
tangare [24]

Answer:

Option D

Step-by-step explanation:

There are no real solution for the given equation

Answered by GAUTHMATH

8 0
2 years ago
Real Answers Only!!!!
lyudmila [28]

Answer:

The correct answer is C) Reflection across the Y-axis.

Step-by-step explanation:

This is because only the x-coordinates changed. If these coordinates were reflected across both the x and y axis' the sign of both the x and y coordinates would have changed. When  you reflect a point across the x axis, the y-coordinates change their sign. When you <u><em>reflect </em></u><u>a point across the y axis</u>, the <u>x-coordinates change</u> their sign.

Hope this helps,

♥<em>A.W.E.</em><u><em>S.W.A.N.</em></u>♥

5 0
3 years ago
Can someone please help me ASAP :)
jeyben [28]
Did this a couple years ago, im kinda lost xD . sorry
4 0
3 years ago
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