4 years ago

Make P the subject of Pt²=2x-Pm a 2

Mathematics

1 answer:

GenaCL600 [577]4 years ago

3 0

Answer:

$p = \frac {2x}{(2t^2 +m)}$

Step-by-step explanation:

$p {t}^{2} = \frac {2x - pm}{2} \\ 2pt^2 = 2x - pm\\2pt^2 +pm= 2x \\p(2t^2 +m) =2x\\\\\huge\purple {\boxed {p = \frac {2x}{(2t^2 +m)}}} \\$

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