Answer:
35.1 units
Step-by-step explanation:
Imagine a right-angled triangle with RS as hypotenuse. The base would be 3 units and the height would be 6 units. By Pythagorus:
RS²=3²+6²
RS=
≈6.7 units
Imagine a right-angled triangle with RT as hypotenuse. The base would be 9 units and the height would be 12 units. By Pythagorus:
RT²=9²+12²
RT=
= 15 units
Imagine a right-angled triangle with TS as hypotenuse. The base would be 12 units and the height would be 6 units. By Pythagorus:
TS²=12²+6²
TS=
≈13.4 units
Perimeter=RS+RT+TS
=6.7+15+13.4
=35.1 units
Answer:
88 x 0.26 = 22.88% or 23%
-7x - 2y = -13
-7x + 7x - 2y = 7x - 13
-2y = 7x - 13
-2 -2
y = -3.5x + 6.5
x - 2y = 11
x - 2(-3.5x + 6.5) = 11
x - 2(-3.5x) - 2(6.5) = 11
x + 7x - 13 = 11
8x - 13 = 11
+ 13 + 13
8x = 24
8 8
x = 3
y = -3.5x + 6.5
y = -3.5(3) + 6.5
y = -10.5 + 6.5
y = -4
(x, y) = (3, -4)
Firstly, you can use the slope and the first point to find a second point:
2 + 1 = x2 and 6 + 5 = y2 because the slope is 5/1.
Next you can write the equation in point-slope form (remember point-slope form is y - y1 = m(x - x1):
y - 11 = 5(x - 3)
Another equation would be B because B is the correct equation if you choose 2 as x2 and 6 as y2.
Hope this helps!
For the first question, simply find a point that is on the line segment. For the second question, knowing that in quadrant iii the x values are negative and the y values are also positive using this fact find the point that has x negative and y positive.
