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iogann1982 [59]
3 years ago
13

2x+5=2x+5 a. infinite solutions b. one solution c. no solution

Mathematics
2 answers:
Alenkinab [10]3 years ago
8 0
I believe the answer would be A!
Mazyrski [523]3 years ago
4 0

Answer:

A) infinite solutions

Step-by-step explanation:

since they are both equal to each other, no matter which value you set x to, they will ALWAYS be each other, no matter what.

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The length of a rectangle is 4 meters longer than the width. if the area is 21 square​ meters, find the​ rectangle's dimensions.
brilliants [131]
The length of a rectangle is 4 meters longer than the width. if the area is 21 square​ meters, find the​ rectangle's dimensions. round to the nearest tenth of a meter.

7 0
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Answer all questions thoroughly, pls!!
Anna11 [10]

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2 years ago
What is GCF and LCM of -5 and 56? Please Help! Will give Brainliest!
Nookie1986 [14]

Answer:

The GCF is 1 and the LCM 280

Step-by-step explanation:

I did this on a test and got it right

4 0
2 years ago
Read 2 more answers
What is the sum of the last 5 terms of the series 1 9 17... 49?
drek231 [11]
The series is increasing by 8 each time.

So that means the complete series is:
1, 9, 17, 25, 33, 41, 49

Add the last 5 digits:
49 + 41 + 33 + 25 + 17 = 165

Answer:
165
4 0
3 years ago
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The lengths of lumber a machine cuts are normally distributed with a mean of 106 inches and a standard deviation of 0.3 inch. ​(
Vinvika [58]

Answer:

a) P(X>106.11)=P(\frac{X-\mu}{\sigma}\frac{106.11-106}{0.3})=P(z>0.37)

And we can find this probability with the complement rule:

P(z>0.37)=1-P(z

b) z =\frac{106.11- 106}{\frac{0.3}{\sqrt{44}}}=  2.431

And if we use the z score we got:

P(z>2.431) =1-P(z

Step-by-step explanation:

Let X the random variable that represent the lengths of a population, and for this case we know the distribution for X is given by:

X \sim N(106,0.3)  

Where \mu=106 and \sigma=0.3

Part a

We are interested on this probability

P(X>106.11)

And we can use the z score formula given by:

z=\frac{x-\mu}{\sigma}

And using this formula we got:

P(X>106.11)=P(\frac{X-\mu}{\sigma}\frac{106.11-106}{0.3})=P(z>0.37)

And we can find this probability with the complement rule:

P(z>0.37)=1-P(z

Part b

For this case we select a sample of n =44 and the new z score formula is given by:

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score we got:

z =\frac{106.11- 106}{\frac{0.3}{\sqrt{44}}}=  2.431

And if we use the z score we got:

P(z>2.431) =1-P(z

6 0
2 years ago
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