Answer:
Step-by-step explanation:
Given definite integral:
<u>Integration by substitution</u>:
Substitute u for one of the functions to give a function that's easier to integrate.
Find the derivative of u and rewrite it so that dx is on its own:
Use the substitution to change the <u>limits</u> of the definite integral from x-values to u-values:
Therefore, the limits are <u>unchanged</u>.
Substitute everything into the original integral and solve:
Learn more about definite integrals here:
brainly.com/question/27954290
Area of a rectangle = length * width
A = 1.6 *1.2 = 1.92 m²
Answer: D. 2550 cm³
<u>Step-by-step explanation:</u>
Volume of one box = Length x width x height
Volume of 6 boxes = 6(L x w x h)
= 6(14 x 6 x 5)
= 6(14 x 30)
= 6(420)
= 2520
Brainly doesn't automatically "know" every part of the problems you post here; you have to ensure that your post includes everything in the original problem.
We can still have some fun with answer choice <span>x = 1, x = 3:
An associated quadratic function would have the form y = a(x-1)(x-3). Just supposing that the point (2, 5) were on the graph, then this </span>y = a(x-1)(x-3) would become 5 = a(2-1)(2-3), or 5 = a(1)(-1), or 5 = -a, or a = -5.
Thus, the equation of the parabola would be y = -5(x-1)(x-3), or, in the more usual form, y = -5(x^2 - 4x + 3).
Complete the square to find the vertex:
Steal y = x^2 - 4x + 3 for a moment and complete the square:
x^2 - 4x + 3 = x^2 - 4x + 4 - 4 + 3, or (x-2)^2 - 1
Subbing this back into y = -5(x^2 - 4x + 3), we get
y = -5 [ (x-2)^2 -1 ], or y = -5(x-2)^2 + 5. This shows that the vertex is at (2, 5), that the graph opens downward, and the graph is symm. about the line x = 2.
Having fun yet?
Answer:
l = 28 cm and b = 4 cm
Step-by-step explanation:
Let the length be l and the breadth be b.
ATQ,
l+b = 32
l=32-b ....(1)
Area of rectangle, A = 112 cm²
We need to find the length and width of the rectangle
The formula for the area of a rectangle is given by :
lb = 112 ...(2)
From equation (1) and (2).
(32-b)b = 112
From above equation, b = 4 cm
Put the value of b in equation (1)
l=32-4
= 28 cm
Hence, the length and width of the rectangle is 28 cm and 4 cm.