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Hoochie [10]
3 years ago
6

What is the equation of a line with a slope of ​3​ and a point (3, 1) on the line?

Mathematics
1 answer:
topjm [15]3 years ago
8 0
The equation of a line that passes through the point (x1,y1) and has a slope of m is
y-y1=m(x-x1)
given
(3,1) and m=3

y-1=3(x-3)
y-1=3x-9
y=3x-8
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X^2 - 36 = 0.
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Answer:

(x+6)(x−6)=0

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Step-by-step explanation:

X^2 - 36 = 0

Solve by Square Root

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x^2−36+36=0+36

x^2=36

square root

x=±√36

x=6 or x=−6

You can do that or for 2nd option

Solve by factoring

x^2-36=0

(x+6)(x−6)=0

Set factors equal to 0

x+6=0 or x−6=0

x=-6 or x=6

PLEASE NOTE: 36 is the square of 6

and

x2  is the square of  x1

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