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Zarrin [17]
2 years ago
6

Linear relationships are important to understand because they are common in the world around you. For example, all rates and rat

ios are linear relationships. Miles per gallon is a common rate used to describe the number of miles a car can travel on one gallon of gasoline. Dollars per gallon, or the price of gas, is a linear relationship as well. What other relationships can you think of that are linear? How do they affect your everyday life?
​
Mathematics
1 answer:
emmasim [6.3K]2 years ago
6 0

Two other examples of linear relationships are changes of units and finding the total cost for buying a given item x times.

<h3>Other examples of linear relationships?</h3>

Two examples of linear relationships that are useful are:

Changes of units:

These ones are used to change between units that measure the same thing. For example, between kilometers and meters.

We know that:

1km = 1000m

So if we have a distance in kilometers x, the distance in meters y is given by:

y = 1000*x

This is a linear relationship.

Another example can be for costs, if we know that a single item costs a given quantity, let's say "a", then if we buy x of these items the total cost will be:

y = a*x

This is a linear relationship.

So linear relationships appear a lot in our life, and is really important to learn how to work with them.

If you want to learn more about linear relationships, you can read:

brainly.com/question/4025726

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Ms Hart had 40 dollars to spend on costume boxes for the musical. If she bought 12 boxes and received 4 dollars in change, how m
artcher [175]

Answer:each box cost =$3

Step-by-step explanation:

Amount of money Ms Hart has to spent on costume boxes=$40

Amount gotten as change after purchase=$4

Amount actually used up buying costume boxes =$40-$4=36

Since she bought 12 boxes , each box cost =$36/ 12=$3

5 0
2 years ago
Let f and g be the functions defined by f(x) = 10^ (x+2 / 3) and g(x) = log (x3 / 100) for all positive real numbers,
Vaselesa [24]

Answer:

F(x) and g(x) are not inverse functions.

Step-by-step explanation:

In order to calculate the inverse function of a function, we have to isolate X and after that, we change the variables.

As our function f(x) is a exponentian function, we can apply logarithm with base 10 (log) in both sides in order to isolate X. Remember that log10=1.

[tex]y=10^{(x+\frac{2}{3}) }\\\\log y=log 10^{(x+\frac{2}{3}) }\\log y = (x+\frac{2}{3}) . log10\\\frac{log Y}{log10} = (x+\frac{2}{3})\\\frac{log Y}{1} = (x+\frac{2}{3})\\log Y-\frac{2}{3}=x[/tex]

Now we change the variables.

F(x)=log x-\frac{2}{3}

F(x) and g(x) are not inverse functions.

4 0
2 years ago
subtract 6/8 - 1/4 enter your answer in the box below as a fraction in lowest terms using the slash ( / ) as the fraction bar
harkovskaia [24]
2/4 but if you reduce you get 1/2
7 0
3 years ago
What is the value of x
Dmitriy789 [7]

x=10 because you add the variables to get 5x and you do 46-6 to get 40. Then you subtract 40 from 90 to get 50 and divide by 5 to get 10 as ur answer.

6 0
3 years ago
Read 2 more answers
Over what interval is the graph of f(x) = –(x + 8)2 – 1 decreasiang<br><br><br><br> help
Degger [83]
Please use " ^ " to denote exponentiation:  

<span>f(x) = –(x + 8)^2 – 1 
Find the first derivative:  f '(x) = -2(x+8)(1)
Set this = to 0:  -2(x+8) = 0
solve for x:  x = -8
Divide the number line into subintervals based upon x=-8:

(-inf, -8) and (-8, inf)

Choose a test value for x from each interval, e. g., -10 from the first interval and 20 from the second.

Subst. this test value into the derivative, shown above.

If the result is + the function is incr on that interval; if - the fn. is decr.

Questions welcome!</span>
5 0
3 years ago
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