Answer:
Proportion of all bearings falls in the acceptable range = 0.9973 or 99.73% .
Step-by-step explanation:
We are given that the diameters have a normal distribution with a mean of 1.3 centimeters (cm) and a standard deviation of 0.01 cm i.e.;
Mean, 
= 1.3 cm and Standard deviation, 
= 0.01 cm
Also, since distribution is normal;
Z = 
~ N(0,1)
Let X = range of diameters
So, P(1.27 < X < 1.33) = P(X < 1.33) - P(X <=1.27)
P(X < 1.33) = P( < 
) = P(Z < 3) = 0.99865
P(X <= 1.27) = P( < 
) = P(Z < -3) = 1 - P(Z < 3) = 1 - 0.99865
= 0.00135
P(1.27 < X < 1.33) = 0.99865 - 0.00135 = 0.9973 .
Therefore, proportion of all bearings that falls in this acceptable range is 99.73% .
All you have to do is plug m and n into the equation:
n+6m
Since n=7, you'll get:
7+6m
And since m=8, you'll get:
7+6(8)
And by doing the order of operations (PEMDAS), you'll start off multiplying 6 and 8, which is 48, then add 7, which is 55.
Your answer should be 55!
The question seems incomplete ; as the total number of tickets to be sold isn't given.
Answer:
61 / X
Step-by-step explanation:
Let's take the total Number of tickets to be sold as : X
Number of tickets sold on Thursday = 47
Number sold on Friday = 14
Fraction of tickets available for sale on Saturday :
(Total number of tickets already sold) / Total number of tickets to be sold
(Thursday + Friday sales) / total number of tickets to be sold
Fraction available for sale on Saturday = (47+14) / X
Fraction available for sale on Saturday = 61 / X
Kindly put value of x = total number of tickets available for sale to get the exact fraction.
Answer:
c- (2x+3)(x+1)
Step-by-step explanation:
Let me know if you want step by step
