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Ira Lisetskai [31]

3 years ago

15

Nicole did an aerobics class and yoga class for at total of 1 hour and 10 minutes. The yoga class was 30 minutes. The yoga class

was 30 minutes longer than the aerobics class. How long was each class.

1 answer:

lana [24]3 years ago

3 0

Yoga class was thirty minutes and the aerobics class was 0 minutes.

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What is 0=r-1 ......

Svet_ta [14]

Answer:

the answer is1

Step-by-step explanation:

ok its actually simple

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1+0=r

you do the problem to get

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What is the answer to this problem?

vovikov84 [41]

Answer:3

Step-by-step explanation:

C = 2()r

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A study of the effect of smoking on sleep patterns is conducted. The measure observed is the time, in minutes, that it takes to

nordsb [41]

Answer:

The group that has greater value of relative dispersion is the smokers group, as the coefficient of variationof their data is bigger than the coefficient of variation of the non-smokers group data.

CV smokers: 0.387

CV non-smokers: 0.234

Step-by-step explanation:

We will calculate the relative dispersion of each data set with its coefficient of variation (ratio of the standard deviation to the arithmetic mean).

Then, first we calculate the mean and standard deviation for the smokers data:

Mean: 43.7

Standard deviation: 286.5

$M_s=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M_s=\dfrac{1}{12}(69.3+56+22.1+47.6+53.2+. . .+13.8)\\\\\\M_s=\dfrac{524.4}{12}\\\\\\M_s=43.7\\\\\\s_s=\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M_s)^2\\\\\\s_s=\dfrac{1}{11}((69.3-43.7)^2+. . . +(13.8-43.7)^2)\\\\\\s_s=\dfrac{3152}{11}\\\\\\s_s=286.5\\\\\\$

The mean and standard deviation for the non-smokers is:

Mean: 30.3

Standard deviation: 50.9

$M_n=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M_n=\dfrac{1}{15}(28.6+25.1+26.4+34.9+28.8+. . .+13.9)\\\\\\M_n=\dfrac{453.8}{15}\\\\\\M_n=30.3\\\\\\s_n=\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M_n)^2\\\\\\s_n=\dfrac{1}{14}((28.6-30.3)^2+. . . +(13.9-30.3)^2)\\\\\\s_n=\dfrac{713.3}{14}\\\\\\s_n=50.9\\\\\\$

Now, we can calculate the coefficient of variation:

CV smokers:

$CV_s=\dfrac{s_s}{M_s}=\dfrac{16.9}{43.7}=0.387$

CV non-smokers:

$CV_n=\dfrac{s_n}{M_n}=\dfrac{7.1}{30.3}=0.234$

3 0

4 years ago

Lauren in making 15 liters of mimosas for a brunch banquet. Orange juice costs her $1.50 per liter and champagne costs her $12 p

PSYCHO15rus [73]

Answer:

10 liters of orange juice
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Step-by-step explanation:

Let c represent the number of liters of champagne Lauren uses. Then (15-c) will be the number of liters of orange juice. The total cost of the mix will be ...

12c +1.50(15-c) = 5.00(15)

10.5c = 52.50 . . . . . subtract 22.50, simplify

52.50/10.5 = c = 5 . . . . divide by the coefficient of c

Then the amount of orange juice is ...

15 -c = 15 -5 = 10 . . . . liters

Lauren should use 5 liters of champagne and 10 liters of orange juice.

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4 years ago

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Vaselesa [24]

B is the correct answer
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3 years ago

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