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3 years ago

Which form of democracy does the United States have?

Mathematics

2 answers:

Vaselesa [24]3 years ago

7 0

B is the correct answer
In the United States we vote on people who represent us so it’s B

mrs_skeptik [129]3 years ago

3 0

B is the answer to your question

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Write the equation of a line that is perpendicular to y=3x-2 and that passes through the point (-9,5)

damaskus [11]

Slope of perpendicular is -1/3.
Then equation is
y-5=(-1/3)(x+9)

8 0

3 years ago

PlZ help I need an answer I don't need to waste points so plz Help!!!!!!!!!

nadya68 [22]

Answer:

The first obe

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

Square root of 81x - square root of 25x

vova2212 [387]

The square root of 81 is 9. The square root of 25 is 5.

5 0

4 years ago

Read 2 more answers

Enter the values for m, n, and p that complete the differences<br> ANSWeR

Novay_Z [31]

n=14, m=3, p=2

Further explanation:

We have to solve the left hand side to check what will be the values of n,m and p

So,

Given

$\frac{7}{x}-\frac{3}{2}$

Taking LCM

$=\frac{14-3x}{2x}$

We divide the LCM with denominator of first fraction and multiply the remainder with the numerator => 14

Then divide the LCM by denominator of second fraction and multiply the remainder with numerator => 3x

Comparing both terms we get

n=14

n=3

p=2

Keywords: Polynomial, Expressions

Learn more about polynomials at:

#LearnwithBrainly

5 0

3 years ago

I need help with finding the answer to a) and b). Thank you!

shtirl [24]

Answer:

$\displaystyle \sin\Big(\frac{x}{2}\Big) = \frac{7\sqrt{58} }{ 58 }$

$\displaystyle \cos\Big(\frac{x}{2}\Big)=-\frac{3 \sqrt{58}}{58}$

$\displaystyle \tan\Big(\frac{x}{2}\Big)=-\frac{7}{3}$

Step-by-step explanation:

We are given that:

$\displaystyle \sin(x)=-\frac{21}{29}$

Where x is in QIII.

First, recall that sine is the ratio of the opposite side to the hypotenuse. Therefore, the adjacent side is:

$a=\sqrt{29^2-21^2}=20$

So, with respect to x, the opposite side is 21, the adjacent side is 20, and the hypotenuse is 29.

Since x is in QIII, sine is negative, cosine is negative, and tangent is also negative.

And if x is in QIII, this means that:

$180$

So:

$\displaystyle 90 < \frac{x}{2} < 135$

Thus, x/2 will be in QII, where sine is positive, cosine is negative, and tangent is negative.

Recall that:

$\displaystyle \sin\Big(\frac{x}{2}\Big)=\pm\sqrt{\frac{1 - \cos(x)}{2}}$

Since x/2 is in QII, this will be positive.

Using the above information, cos(x) is -20/29. Therefore:

$\displaystyle \sin\Big(\frac{x}{2}\Big)=\sqrt{\frac{1 + 20/29}{2}$

Simplify:

$\displaystyle \sin\Big(\frac{x}{2}\Big)=\sqrt{\frac{49/29}{2}}=\sqrt{\frac{49}{58}}=\frac{7}{\sqrt{58}}=\frac{7\sqrt{58}}{58}$

Likewise:

$\displaystyle \cos \Big( \frac{x}{2} \Big) =\pm \sqrt{ \frac{1+\cos(x)}{2} }$

Since x/2 is in QII, this will be negative.

Using the above information, cos(x) is -20/29. Therefore:

$\displaystyle \cos \Big( \frac{x}{2} \Big) =-\sqrt{ \frac{1- 20/29}{2} }$

Simplify:

$\displaystyle \cos\Big(\frac{x}{2}\Big)=-\sqrt{\frac{9/29}{2}}=-\sqrt{\frac{9}{58}}=-\frac{3}{\sqrt{58}}=-\frac{3\sqrt{58}}{58}$

Finally:

$\displaystyle \tan\Big(\frac{x}{2}\Big) = \frac{\sin(x/2)}{\cos(x/2)}$

Therefore:

$\displaystyle \tan\Big(\frac{x}{2}\Big)=\frac{7\sqrt{58}/58}{-3\sqrt{58}/58}=-\frac{7}{3}$

5 0

3 years ago