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liubo4ka [24]
3 years ago
13

To win at LOTTO in a certain state, one must correctly select 6 numbers from a collection of 52 numbers (1 through 52). The orde

r in which the selections is made does not matter. How many different 6-number selections are possible?
Mathematics
1 answer:
miv72 [106K]3 years ago
7 0

Answer:

The answer is 20,358,520

Step-by-step explanation:

Selecting 6 numbers from a collection of 52 numbers regardless of order involves a combination.

Note: if regards was taken into order of selection, this would be a permutation.

Hence, the different 6 number selections out of 52 is

52C6 = 52! / [6!*(52-6)!]

= 52!/(6!*46!)

= 20,358,520

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 and R(10)=18*10=180.


So if only 10 units are produced, the total cost is 36,160, while the revenue is only 180 (again, say $.)



If, for example, x=1000, then we can calculate 

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and 

R(1000)=18*1000=18,000.


This suggests that with higher values of x, we can get to a particular point where the Cost and Revenue are the same. To find this point, we set the equation:
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which gives us that particular x at which both </span>C(x) and R(x) give the same value.

Thus, we solve <span>16x+36,000=18x. Subtracting 16x from both sides                                                         2x=36,000,   then x = 36,000/2=18,000.


 
Answer: 18,000

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Step-by-step explanation:

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Step-by-step explanation:

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