Evaluate (2 a + b)^2/(3 b - 1) where a = -2 and b = 5:
(2 a + b)^2/(3 b - 1) = (5 - 2×2)^2/(3×5 - 1)
3×5 = 15:
(5 - 2×2)^2/(15 - 1)
| 1 | 5
- | | 1
| 1 | 4:
(5 - 2×2)^2/14
2 (-2) = -4:
(-4 + 5)^2/14
5 - 4 = 1:
1^2/14
1^2 = 1:
Answer: 1/14
Answer:
No
Step-by-step explanation:
To see if (2,2) is a solution, substitute them into the inequality and see if it is true.
2 is our x value, and 2 is also our y value
y < 4x – 6
2< 4(2)– 6
2 < 8 – 6
2 < 2
This statement is false. 2 is not less than 2, so (2,2) is not a solution to this equation.
Answer: m1+m3
Step-by-step explanation: 1+3=4 and m1+m3 has the same varibles in the expression.
Answer:
Step-by-step explanation:
ACB is an inscribed angle
so ∠ACB = 1/2 mAB
Hence we got
Answer:
what is the question? this is a statement...
