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2 years ago

Find the area of the unshaded portion of

Mathematics

1 answer:

Nostrana [21]2 years ago

8 0

Answer: 3055.25

Step-by-step explanation:

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Y=15-4y what is the answer Y=___

Dominik [7]

Y=15 -4y
+4y +4y
5y=15
÷ ÷
5 5
y=3

6 0

3 years ago

Suppose that the length of a side of a cube X is uniformly distributed in the interval 9

Nastasia [14]

Answer:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

Step-by-step explanation:

Given

$9 < x < 10$ --- interval

Required

The probability density of the volume of the cube

The volume of a cube is:

$v = x^3$

For a uniform distribution, we have:

$x \to U(a,b)$

and

$f(x) = \left \{ {{\frac{1}{b-a}\ a \le x \le b} \atop {0\ elsewhere}} \right.$

$9 < x < 10$ implies that:

$(a,b) = (9,10)$

So, we have:

$f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Solve

$f(x) = \left \{ {{\frac{1}{1}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Recall that:

$v = x^3$

Make x the subject

$x = v^\frac{1}{3}$

So, the cumulative density is:

$F(x) = P(x < v^\frac{1}{3})$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$ becomes

$f(x) = \left \{ {{1\ 9 \le x \le v^\frac{1}{3} - 9} \atop {0\ elsewhere}} \right.$

The CDF is:

$F(x) = \int\limits^{v^\frac{1}{3}}_9 1\ dx$

Integrate

$F(x) = [v]\limits^{v^\frac{1}{3}}_9$

Expand

$F(x) = v^\frac{1}{3} - 9$

The density function of the volume F(v) is:

$F(v) = F'(x)$

Differentiate F(x) to give:

$F(x) = v^\frac{1}{3} - 9$

$F'(x) = \frac{1}{3}v^{\frac{1}{3}-1}$

$F'(x) = \frac{1}{3}v^{-\frac{2}{3}}$

$F(v) = \frac{1}{3}v^{-\frac{2}{3}}$

So:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

8 0

2 years ago

Brian has 40000 to invest in a mix of corporate and municipal bonds. The corporate bond pays 10% simple annual interest and the

jonny [76]

Answer:

Sum of money invested in corporate bonds = 30,000

Step-by-step explanation:

Total sum = 40,000

The rate of interest for corporate bonds = 10 % = 0.1

The rate of interest for municipal bonds = 6 % = 0.06

Total interest = 3600

Let sum of money invested in corporate bonds = x

The sum of money invested in municipal bonds = 40000 - x

$x$ × 0.1 × 1 + ( $40000 - x$ ) × 0.06 × 1 = 3600

(0.1- 0.06) $x$ + 2400 = 3600

0.04 $x$ = 1200

$x$ = 30,000

Since x = sum of money invested in corporate bonds

So sum of money invested in corporate bonds = 30000

4 0

3 years ago

the mean of 10 students is 16 . When a student is added, the mean becomes 18. Find the age of the student added

MakcuM [25]

Answer:

Step-by-step explanation:

5 0

3 years ago

Student had 500 milliliters of water in a water bottle. She drank 25% of the water before soccer practice. After practice, she d

sesenic [268]

250 milliters of water remains

8 0

2 years ago