Can someone help me, please. :(
2 answers:
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<h3>Jason bought 20 stamps of $0.41 each and 8 postcards of $0.26 each.</h3>
<em><u>Solution:</u></em>
Let stamps be s and postcards be p
Given that,
The number of stamps was 4 more than twice the number of postcards
s = 4 + 2p -------- eqn 1
Jason bought both 41-cent stamps and 26-cent postcards and spent $10.28
41 cent = $ 0.41
26 cent = $ 0.26
Therefore,
0.41s + 0.26p = 10.28 --------- eqn 2
Substitute eqn 1 in eqn 2
0.41(4 + 2p) + 0.26p = 10.28
1.64 + 0.82p + 0.26p = 10.28
1.08p = 10.28 - 1.64
1.08p = 8.64
Divide both sides by 1.08
p = 8
Substitute p = 8 in eqn 1
s = 4 + 2(8)
s = 4 + 16
s = 20
Thus Jason bought 20 stamps and 8 post cards
You can use the fact that two expressions in equality can be considered to be equal to a third variable(not used in given context).
The system of equations that could be graphed to solve the equation given is
Suppose the equation be
Let there is a symbol such that we have
It is because a and b are same measure (that is exactly what a = b means)
and we gave another name c to that measure.
Thus, we have
in addition to
Since the given equation is
The 2d graphs are usually expressed as on X-Y plane.
Taking the equation's expressions equal to y, we get
or, we get system of equations as
Their graph is plotted below. The intersection point of both curves is the solution to the given equation as it satisfies both the equations of the system of equations formed from the given equation.
Thus,
The system of equations that could be graphed to solve the equation given is
Learn more about solutions to system of equations here:
