The radius is half the diameter. So do 4.1 times 3.14 for the circumference. :)
The correct ratio for this problem is 3:4
<h2>The steps:</h2><h2>1) make 45 and 60 a fraction </h2><h2>2)45/60 simplify </h2><h2>3) once you simplfy you should get 3/4</h2><h2 /><h2>Steps in Numbers:</h2><h2>45/60 =3/4</h2><h2>60/45=4/3 convert 3/4</h2><h2>3/60=1/20 </h2><h2>3/45=1/15</h2><h2>Step 3:</h2><h2>60 divided into 48 as a fraction and simplify it </h2>
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
![g(h(x)) = \sqrt[4]{x^2 + x +5} + 3](https://tex.z-dn.net/?f=g%28h%28x%29%29%20%3D%20%5Csqrt%5B4%5D%7Bx%5E2%20%2B%20x%20%2B5%7D%20%2B%203)
b
![h(g(x)) = \sqrt{x} + 7\sqrt[4]{x} + 17](https://tex.z-dn.net/?f=h%28g%28x%29%29%20%20%3D%20%5Csqrt%7Bx%7D%20%20%2B%207%5Csqrt%5B4%5D%7Bx%7D%20%2B%2017)
c
![h(h(x)) = [x^2 + x + 5 ]^2 + x^2 + x + 10](https://tex.z-dn.net/?f=h%28h%28x%29%29%20%3D%20%20%5Bx%5E2%20%2B%20x%20%2B%205%20%5D%5E2%20%2B%20x%5E2%20%2B%20x%20%2B%2010)
Step-by-step explanation:
From the question we are told that
and
![g(x) = \sqrt[4]{x} + 3](https://tex.z-dn.net/?f=g%28x%29%20%3D%20%5Csqrt%5B4%5D%7Bx%7D%20%2B%203)
Considering first question
Now we are told g(h(x))
i.e
![g(h(x)) = [x^2 + x + 5 ]^{\frac{1}{4} } + 3](https://tex.z-dn.net/?f=g%28h%28x%29%29%20%3D%20%20%5Bx%5E2%20%2B%20x%20%2B%205%20%5D%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%20%2B%203)
=>
Considering second question
Now we are told h(g(x))
i.e
![h(g(x)) = [x^{\frac{1}{4} } + 3]^2 + x^{\frac{1}{4} } + 3 + 5](https://tex.z-dn.net/?f=h%28g%28x%29%29%20%3D%20%20%5Bx%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%20%2B%203%5D%5E2%20%2B%20%20x%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%20%2B%203%20%2B%205)
=> 
=> 
=>
Considering third question
![h(h(x))= [x^2 + x + 5]^2 + [x^2 + x + 5 ] + 5](https://tex.z-dn.net/?f=h%28h%28x%29%29%3D%20%5Bx%5E2%20%2B%20x%20%2B%205%5D%5E2%20%2B%20%5Bx%5E2%20%2B%20x%20%2B%205%20%5D%20%2B%20%205)
=>
Answer:
16
Step-by-step explanation:
mark it as the Brainliest
Answer:
Xkilomotore
Step-by-step explanation:
tha X is a xearneas
