Question

There are 40 students,

Answer 1

answer

$\frac{621}{2000}$ ≈ 0.31 = 31 %

set up equation

the probability of someone from the first group having brown eyes is $\frac{students-with-brown-eyes-in-first-group}{total-students-in-first-group }$

the probability of someone from the second group having brown eyes is $\frac{students-with-brown-eyes-in-second-group}{total-students-in-second-group }$

so the probability of both students having brown eyes is$\frac{students-with-brown-eyes-in-first-group}{total-students-in-first-group }$*$\frac{students-with-brown-eyes-in-second-group}{total-students-in-second-group }$

values

students with brown eyes in first group = 27

total students in first group = 40

students with brown eyes in second group = 23

total students in second group = 50

plug in values and solve

$\frac{students-with-brown-eyes-in-first-group}{total-students-in-first-group }$*$\frac{students-with-brown-eyes-in-second-group}{total-students-in-second-group }$

= $\frac{27}{40} *\frac{23}{50}$

= $\frac{27 * 23}{40 * 50}$

= $\frac{621}{2000}$

≈ 0.31

= 31 %