
<u>Step-by-step explanation:</u>
We have ,
,
We know that ![sin\alpha = \frac{Perpendicular}{Hypotenuse} = \frac{Perpendicular}{\sqrt[2]{(Perpendicualr)^{2} + (Base)^{2})} }](https://tex.z-dn.net/?f=sin%5Calpha%20%20%3D%20%5Cfrac%7BPerpendicular%7D%7BHypotenuse%7D%20%3D%20%5Cfrac%7BPerpendicular%7D%7B%5Csqrt%5B2%5D%7B%28Perpendicualr%29%5E%7B2%7D%20%2B%20%28Base%29%5E%7B2%7D%29%7D%20%7D)
Substituting values of P & B , 
Now , 
⇒
×
×2
⇒ 
⇒
⇒
⇒
You multiply the exponents together to get a single exponent, in this case, 15
9/20
explanation:
7/10 - 1/4
14/20 - 5/20
14-5/20
9/20
Answer
do u have a demonstration
picture
Step-by-step explanation:
I’m pretty sure the answer would be Y=42°