Please help me I will fail the exam help me please
1 answer:
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Answer:
CE = 17
Step-by-step explanation:
∵ m∠D = 90
∵ DK ⊥ CE
∴ m∠KDE = m∠KCD⇒Complement angles to angle CDK
In the two Δ KDE and KCD:
∵ m∠KDE = m∠KCD
∵ m∠DKE = m∠CKD
∵ DK is a common side
∴ Δ KDE is similar to ΔKCD
∴
∵ DE : CD = 5 : 3
∴
∴ KD = 5/3 KC
∵ KE = KC + 8
∵
∴
∴
∴
∴
∴ KC = (8 × 9) ÷ 16 = 4.5
∴ KE = 8 + 4.5 = 12.5
∴ CE = 12.5 + 4.5 = 17
Answer:
x=5
y=4
Step-by-step explanation:
Step 1:
Let us solve for <em>x</em> using the equation by <u>isolating terms containing the variable</u>:
Great! <em>x</em> is 5... let's find <em>y</em>.
Step 2:
Since we know the value of <em>x</em>, we can use what we know to find <em>y</em> using the <u>other equation</u>:
<em>Given that x=5, we can </em><u><em>replace</em></u><em> x with 5</em>.
<em>I hope this helps! Let me know if you have any questions :)</em>