Please help me I will fail the exam help me please

Serggg [28]

Use the law of sines....(sina/A=sinb/B=sinc/C for any triangle)

What that means is the sine of an angle divided by the length of the side opposite the angle is a ratio that is true each angle/side pair...In this case:

sin90/122=sinc/22 rearrange to solve for sinc

sinc=(22sin90)/122 now take the arcsin to solve for c

c=arcsin[(22sin90)/122]

c≈10.388857815469611987441020361405

c≈10.39° (to nearest hundredth of a degree)

3 0

3 years ago

What is the solution to the equation StartFraction 3 Over m + 3 EndFraction minus StartFraction m Over 3 minus m EndFraction = S

Oksanka [162]

Answer:

No solution.

Step-by-step explanation:

Given fraction is:

$\dfrac{3}{m+3} -\dfrac{m}{3-m} = \dfrac{m^2+9}{m^2-9}\\\Rightarrow \dfrac{3}{m+3} +\dfrac{m}{m-3} = \dfrac{m^2+9}{m^2-9}\\\Rightarrow \dfrac{3\times (m-3)+ m(m+3)}{(m+3)(m-3)} = \dfrac{m^2+9}{m^2-9}\\\Rightarrow \dfrac{3 m-9+ m^2+3m}{m^2-9} = \dfrac{m^2+9}{m^2-9}\\\Rightarrow \dfrac{m^2-9+ 6m}{m^2-9} = \dfrac{m^2+9}{m^2-9}\\If\ m^2-9 \neq 0\ or\ m \neq 3\\\Rightarrow m^2-9+ 6m = m^2+9\\\Rightarrow 6m = 18\\\Rightarrow m = 3$

<u>Formula used:</u>

<u></u>

But, the above equation was solved at the condition that:

$m\neq 3$

So, there is no solution for the given equation.

3 0

3 years ago

Read 2 more answers

Six students are working to simplify the expression shown. Drag each student's answer to a box to show whether it is fully simpl

saveliy_v [14]

Answer:

there is no picture included, but to help just look at your expression and say to yourself can we do any more with these numbers, if yes, they are not simplified, if no, then they are simplified.

Step-by-step explanation:

5 0

3 years ago

One, no, or infinitely many solutions?

erastovalidia [21]

Answer:

One solution

x = 3

Step-by-step explanation:

3x + 5 + 6x - 7 = 25

combine like terms:

9x -2 = 25

add 2 to each side of the equation:

9x = 27

divide both sides by n9:

x = 3

3 0

3 years ago

Round to the nearest whole %

Otrada [13]

The relative frequency for middle school students whose favourite sport is baseball is 27%.

The relative frequency for middle school students whose favorite sport is basketball is 31%.

The relative frequency for middle school students whose favorite sport is football is 42%.

The relative frequency for high school students whose favorite sport is baseball is 44%.

The relative frequency for high school students whose favorite sport is basketball is 31%

The relative frequency for high school students whose favorite sport is football is 25%

<h3>What is relative frequency?</h3>

Relative frequency measures how often a value appears relative to the sum of the total values.

The relative frequency for middle school students whose favourite sport is baseball = 13/48 = 27%

The relative frequency for middle school students whose favorite sport is basketball = 15 / 48 = 31%

The relative frequency for middle school students whose favorite sport is football = 20 / 48 = 42%

The relative frequency for high school students whose favorite sport is baseball = 23 / 52 = 44%

The relative frequency for high school students whose favorite sport is basketball = 16 / 52 = 31%

The relative frequency for high school students whose favorite sport is football = 13 / 52 = 25%

To learn more about relative frequency, please check: brainly.com/question/14610326

5 0

2 years ago