It would not have an effect on the gross income. Hope this helps
<span>a^3 - b^3 = (a - b) </span><span>(<span>a^2 + </span>ab + b^2)
</span><span>so
x^3 - 4^3 = (x - 4)(x^2 + 4x + 16)
hope it helps</span>
(a)
Q1, the first quartile, 25th percentile, is greater than or equal to 1/4 of the points. It's in the first bar so we can estimate Q1=5. In reality the bar includes values from 0 to 9 or 10 (not clear which) and has around 37% of the points so we might estimate Q1 a bit higher as it's 2/3 of the points, say Q1=7.
The median is bigger than half the points. First bar is 37%, next is 22%, so its about halfway in the second bar, median=15
Third bar is 11%, so 70% so far. Four bar is 5%, so we're at the right end of the fourth bar for Q3, the third quartile, 75th percentile, say Q3=40
b
When the data is heavily skewed left like it is here, the median tends to be lower than the mean. The 5% of the data from 80 to 120 averages around 100 so adds 5 to the mean, and 8% of the data from the 60 to 80 adds another 5.6, 15% of the data from 40 to 60 adds about 7.5, plus the rest, so the mean is gonna be way bigger than the median of around 15.
Answer:
{3, 4, 5, 6, 7, 8, 9, 10, 11}
Step-by-step explanation:
Let integer be x
x > 2 and x < 12
gives
2 < x < 12
All such integers are {3, 4, 5, 6, 7, 8, 9, 10, 11}
