Describe and correct the error in rewriting the equation

Connor took out a 4 year loan to buy a car at a 4% simple interest rate. if he has to pay $240 in interest, how much principal d

uysha [10]

Answer:

The principal borrow for loan is $1,500 .

Step-by-step explanation:

Given as :

The interest paid on simple interest = s.i = $240

The rate of simple interest applied = r = 4%

The time period for loan = t = 4 years

Let The principal borrow = $p

Now, from Simple Interest method

Simple Interest = $\dfrac{\textrm principal\times \textrm rate\times \textrm time}{100}$

Or. s.i = $\dfrac{\textrm p\times \textrm r\times \textrm t}{100}$

Or, $240 = $\dfrac{\textrm p\times \textrm 4\times \textrm 4}{100}$

Or, $240 × 100 = 16 × p

Or, $24000 = 16 × p

∴ p = $\dfrac{24000}{16}$

i.e p = $1,500

So, The principal borrow for loan = p = $1,500

Hence, The principal borrow for loan is $1,500 . Answer

3 0

3 years ago

Either use technology to find the P-value or use

Akimi4 [234]

Answer:

The first step is calculate the degrees of freedom, on this case:

$df=n-1=21-1=20$

Since is a one side left tailed test the p value would be:

$p_v =P(t_{(20)}$

And we can use the following excel code to find it: "=T.DIST(-0.024,20,TRUE)"

Step-by-step explanation:

Data given and notation

$\bar X$ represent the mean

$s$ represent the sample standard deviation

$n=21$ sample size

$\mu_o =140$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t=-0.024 would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean for the widths of tornadoes is lower than 140 yd, the system of hypothesis would be:

Null hypothesis: $\mu \geq 140$

Alternative hypothesis: $\mu < 140$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

The statistic is given by: $t = -0.024$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=21-1=20$

Since is a one side left tailed test the p value would be:

$p_v =P(t_{(20)}$

And we can use the following excel code to find it: "=T.DIST(-0.024,20,TRUE)"

Based on the p value obtained we can conclude that we FAIL to reject the null hypothesis at any significance level selected $\alpah=0.01,0.05,0.1$

7 0

3 years ago

Someone please help me I’m so confused!!!

QveST [7]

Answer:

number one. 186 $in^{2}$ number two. 36 $cm^{2}$

Step-by-step explanation:

FOR NUMBER ONE:

the area of a trapezoid formula is $\frac{a+b}{2} h$ where a and b are the bases and h is the height. so we have to add in the numbers into the formula

$\frac{12+15}{2} * 6\\$ = 81

and the paralellogram formula is b×h. where b is the base and h is height

15 × 7 = 105

so the area of the figure is 81 + 105 is 186 in^2

FOR NUMBER TWO:

the area of the square formula is $s^{2}$ . where s is the side

4^2 = 16

and for the paralellogram is b × h

4 × 5 = 20

so the area of the figure is 16 +20 = 36 in^2

hope this helps! ;)

5 0

3 years ago

Solve the equation. Round to the nearest hundredth. Show work.

Burka [1]

Answer:

$x=-0.75$

Step-by-step explanation:

The given equation is

$4^{-5x-7}=6^{2x-1}$

We take logarithm of both sides to base 10.

$\log(4^{-5x-7})=\log(6^{2x-1})$

$(-5x-7)\log(4)=(2x-1)\log(6)$

We expand the brackets to get;

$-5x\log(4)-7\log(4)=2x\log(6)-\log(6)$

Group similar terms;

$-7\log(4)+\log(6)=2x\log(6)+5x\log(4)$

$-7\log(4)+\log(6)=(2\log(6)+5\log(4))x$

$\frac{-7\log(4)+\log(6)}{(2\log(6)+5\log(4))}=x$

$x=-0.752478$

To the nearest hundredth.

$x=-0.75$

3 0

3 years ago

Jacob wanted to know what the most popular sneakers brand was for his classmates. His class had 30students. To save time he aske

Galina-37 [17]

No. This is not random sampling as the students chose are not chosen at random. Random sampling would be something done where each sample has equal probability of being chosen. Clearly this is not random sampling.

7 0

3 years ago