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3 years ago

Find the area of the figure.

Mathematics

1 answer:

givi [52]3 years ago

4 0

these are just two semi-circles, one with a diameter of 22 and the other with a diameter of 30 - 22, or 8, and therefore their radius are 11 and 4 respectively.

$\bf \textit{area of a semi-circle}\\\\ A=\cfrac{\pi r^2}{2}~~,~~ \stackrel{r=11}{A=\cfrac{\pi 11^2}{2}}\implies A=\cfrac{121\pi }{2}~~,~~ \stackrel{r=4}{A=\cfrac{\pi 4^2}{2}}\implies A=8\pi \\\\ -------------------------------\\\\ \stackrel{\textit{total area of the figure}}{\cfrac{121\pi }{2}+8\pi }\implies \cfrac{121\pi +16\pi }{2}\implies \cfrac{137\pi }{2}$

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Plsss help no one answered the other times I put this question

svetlana [45]

Answer:

a) The equation (10s + 8w) represents the calories Bridget ate on Monday and the equation (20s + w) represents the calories she ate the next day.

b) The number of calories in each strawberry is 4 and the number of calories in each vanilla wafer cookie is 19. The solution is s= 4 and w = 19.

Step-by-step explanation:

For part A, Bridget ate 10 strawberries and 8 vanilla wafer cookies on Monday. Since the the number of calories in a strawberry is s and the number of calories in a vanilla wafer cookie is w , the number of calories Bridget ate on Monday is 10s + 8w. The next day, Bridget ate 20 strawberries and 1 vanilla wafer cookie. Hence, the number of calories Bridget ate on the next day is 20s + w.

For part B,

we will create two different simultaneous equations.

Equation 1: 10s + 8w = 192

Equation 2: 20s + w = 99

We need to find one of the terms first to solve the other term. For this case, I will solve for w first.

Multiply the first equation by 2.

Equation 3: 20s + 16w = 192*2 = 384.

Now, subtract equation 2 from this new equation.

Equation 4:

(20s + 16w) - (20s + w) = 384 - 99

20s + 16w - 20s - w = 285

15w = 285

This leaves only w left and we can solve w.

w = 285 / 15 = 19

Now, we can solve for s using equation 2.

20s + 19 = 99

20s = 99-19 = 80

Hence,

s = 80/20 = 4

7 0

3 years ago

The principal observes 8th grade the following day. Of the 120 students, 42 brought their lunch from home, 72 purchased lunches,

Rama09 [41]

Answer:

i pretty sure i do not know that answer to be honest

Step-by-step explanation:

i believe this because i dont know anything about this im still lost

8 0

2 years ago

The five members of the Traynor family each buy train tickets. During the train ride, each family member buys a boxed lunch for

larisa [96]

Let's assume

the price of each train ticket is x

we are given

total number of family members =5

so, total cost of ticket = total number of family members*the price of each ticket

so, total cost of ticket =5*x

so, total cost of ticket =5x

now, we have

each family member buys a boxed lunch for $6.50

so, total cost of lunch box = total number of family members*price of each lunch box

so, total cost of lunch box = 5*6.50

total cost of trip = total cost of ticket+total cost of lunch box

we are given

total cost of trip is $248.50

now, we can plug values

and we get

$248.50=5x+5*6.50$

now, we can solve for x

$248.50=5x+32.5$

$248.50-32.5=5x+32.5-32.5$

$216=5x$

$\frac{5x}{5} =\frac{216}{5}$

$x=43.2$

so,

the price of each train ticket is $43.2..........Answer

8 0

3 years ago

Read 2 more answers

Jim provides photos for two online sites: site A and site B. Site A pays $0.85 for every photo Jim provides. The amount in dolla

yarga [219]

We can use the same equation to figure out with only substituting the amount he was paid per photo.

Site A y = $0.85x = $0.85(5) = $4.25
Site B y = $0.40x = $0.40(5) = $2.00

We can see that Jim was paid $2.25 more at site A than Site B.

6 0

3 years ago

Read 2 more answers

Which is the better price- 17% off $35 or 12% off $32?Explain

butalik [34]

Despite having a lower percentage, the one with 12% off manages to have a better price in the long run do the starting price.

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3 years ago