<span>Often the university sites exist primarily for internal use, listing equipment and demos available to physics professors teaching large sections of introductory courses. They usually give lists of required equipment, they don't always give much information about setup, effective presentation and explanation of the physics.</span>
For the first one the nth term is 9n - 8 so the 10th term is 9x10 - 8 = 90-8 = 82
For the second one the nth term is ⅓n + ⅓ so the 11th term is ⅓x11 +⅓ = 3.9999 = 4
Answer:
it is 9
Step-by-step explanation:
you add the 4 and times 3
0.9% / 100% = 0.009
= 9/1000
equivalent ratio:
9/1000 = 153/x
cross multiply
9x = 153,000
x = 153,000/9
x = 17,000
153/17,000 = 0.009
