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erik [133]
3 years ago
9

4

qrt{5} \times 3 \sqrt{5 } " alt="4 \sqrt{5} \times 3 \sqrt{5 } " align="absmiddle" class="latex-formula">
5х35​
Mathematics
1 answer:
Ann [662]3 years ago
4 0

Answer:

60

Step-by-step explanation:

4 sqrt(5) * 3 sqrt(5) =

12 sqrt(5) sqrt(5)

12 *5

60

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Use the equation m Subscript PQ Baseline equals StartFraction f left parenthesis x 1 plus h right parenthesis minus f left paren
babunello [35]

Answer:

  m = 12

Step-by-step explanation:

For f(x) = 2x² you want to find the slope m using ...

  m = (f(x+h) -f(x))/h

at x=3.

Filling in the function definition and its arguments, we have ...

  m = (2(x+h)² -2x²)/h = (2x² +4hx +2h² -2x²)/h = 4x +2h

The value of this as h goes to zero is ...

  m = 4x

At x=3, the slope is ...

  m = 4·3 = 12

_____

The attached graph shows a numerical estimate of the slope (f'(3)=12) and the line with that slope through the point P(3, 18). The line certainly appears to be tangent to the curve at that point.

3 0
3 years ago
What is the equation of the line that has a slope of -3 and passes through the point (-4,-2)
Vikentia [17]

Answer:

y=-3x-14

Step-by-step explanation:

7 0
3 years ago
Factor the expression y4 − 81 using the polynomial identity (x2 − y2) = (x − y)(x + y).
katrin [286]
The factored form is (y^2+9)(y^2-9).

Plug the two terms into the equation by finding the root of both.
√y^4= y^2
√81= 9

From here, you plug the terms into the form (x+y)(x-y)
(y^2+9)(y^2-9)

Hope this helps!
6 0
3 years ago
A parabola can be drawn given a focus of (4,-7) and a directrix of y=5. Write the equation of the parabola in any form
ch4aika [34]
Just started susie hw
7 0
4 years ago
3x+7y-12 where x=-4 and y= 6 *
erik [133]

Replace x any with their values:

3(-4) + 7(6) -12

Simplify:

-12 + 42 -12

Solve:

-12 + 42 -12 = 42

6 0
3 years ago
Read 2 more answers
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