The equation of the perpendicular line to the given line is: y = -5/4x - 30.
<h3>What is the Equation of Perpendicular Lines?</h3>
The slope values of two perpendicular lines are negative reciprocal of each other.
Given that the line is perpendicular to y = 4/5x+23, the slope of y = 4/5x+23 is 4/5. Negative reciprocal of 4/5 is -5/4.
Therefore, the line that is perpendicular to it would have a slope (m) of -5/4.
Plug in m = -5/4 and (x, y) = (-40, 20) into y = mx + b to find b:
20 = -5/4(-40) + b
20 = 50 + b
20 - 50 = b
b = -30
Substitute m = -5/4 and b = -30 into y = mx + b:
y = -5/4x - 30
The equation of the perpendicular line is: y = -5/4x - 30.
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II(RS is a median) and III(RS is a side of RST)
Answer:
steps 2 and 3 must be switched
Step-by-step explanation:
e2020
Answer:
The rock hits the ground between <u>2</u> seconds and <u>2.5</u> seconds after it is dropped
Step-by-step explanation:
The given table is presented as follows;

Therefore, the rock hits the ground between t = 2 seconds and t = 2.5 seconds after it is dropped.