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umka2103 [35]
3 years ago
5

How Do You Solve This? 4x+1-x=2x-13+5?

Mathematics
2 answers:
ratelena [41]3 years ago
7 0
The answer to the question

tiny-mole [99]3 years ago
7 0

x=-9 that should be my answer


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Solve for x.<br> −7≥13−5x
Sergio039 [100]

Answer:

\[=>x\geq 4\]

Step-by-step explanation:

Given inequality is \[−7\geq13−5x\]

Simplifying:

\[5x\geq13+7\]

\[=>5x\geq20\]

\[=>x\geq \frac{20}{5}\]

\[=>x\geq 4\]

Hence the solution for the given inequality is represented by  \[=>x\geq 4\]

This means that the original inequality will be true only for those values of x which are greater than or equal to 4.

4 0
3 years ago
Solving equations with rational numbers
Nonamiya [84]

Answer:

P= 2

T=6

3) 252$

Step-by-step explanation:

1) set up your equation 3/8p=6/8 then divide 3/8 from both sides (remember when you divide fractions you would multiply by the reciprocal so 3/8 x 8/6. Also make sure you simplify)

2) Do the same here. 38/7 divided by 19/21

3) Turn the fraction into an improper fraction then multiply 126 by that amount (3/6)

6 0
3 years ago
Choose and appropriate data display for the situation. Select all that apply.
Ronch [10]

Answer:4

Step-by-step explanation: i think not sure

3 0
3 years ago
How many gallons of a 80% antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get a mixture that is 70% antif
konstantin123 [22]

440 gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get a mixture that is 70% antifreeze

<em><u>Solution:</u></em>

Let "x" be the gallons of 80 % antifreeze added

Therefore, "x" gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze

Final mixture is x + 80

Therefore, we can frame a equation as:

"x" gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get (x + 80) gallons of 70 % antifreeze

Thus, we get,

x gallons of 80 % + 80 gallons of 15 % = (x + 80) gallons of 70 %

x \times \frac{80}{100} + 80 \times \frac{15}{100} = (x+80) \times \frac{70}{100}\\\\0.8x + 80 \times 0.15 = (x+80) \times 0.7\\\\0.8x+12 = 0.7x+56\\\\0.8x-0.7x=56-12\\\\0.1x = 44\\\\x = \frac{44}{0.1}\\\\x = 440

Thus 440 gallons of 80 % antifreeze solution must be mixed

4 0
3 years ago
Uhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh
Dovator [93]

Answer:

hiiiiiiiiiiiiiiiiiiiiiiiiiiihhhhhhhhhrrrrrrrrruuuuuuu

5 0
3 years ago
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