Answer:
![\[=>x\geq 4\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Ex%5Cgeq%204%5C%5D)
Step-by-step explanation:
Given inequality is ![\[−7\geq13−5x\]](https://tex.z-dn.net/?f=%5C%5B%E2%88%927%5Cgeq13%E2%88%925x%5C%5D)
Simplifying:
![\[5x\geq13+7\]](https://tex.z-dn.net/?f=%5C%5B5x%5Cgeq13%2B7%5C%5D)
![\[=>5x\geq20\]](https://tex.z-dn.net/?f=%5C%5B%3D%3E5x%5Cgeq20%5C%5D)
![\[=>x\geq \frac{20}{5}\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Ex%5Cgeq%20%5Cfrac%7B20%7D%7B5%7D%5C%5D)
![\[=>x\geq 4\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Ex%5Cgeq%204%5C%5D)
Hence the solution for the given inequality is represented by ![\[=>x\geq 4\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Ex%5Cgeq%204%5C%5D)
This means that the original inequality will be true only for those values of x which are greater than or equal to 4.
Answer:
P= 2
T=6
3) 252$
Step-by-step explanation:
1) set up your equation 3/8p=6/8 then divide 3/8 from both sides (remember when you divide fractions you would multiply by the reciprocal so 3/8 x 8/6. Also make sure you simplify)
2) Do the same here. 38/7 divided by 19/21
3) Turn the fraction into an improper fraction then multiply 126 by that amount (3/6)
Answer:4
Step-by-step explanation: i think not sure
440 gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get a mixture that is 70% antifreeze
<em><u>Solution:</u></em>
Let "x" be the gallons of 80 % antifreeze added
Therefore, "x" gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze
Final mixture is x + 80
Therefore, we can frame a equation as:
"x" gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get (x + 80) gallons of 70 % antifreeze
Thus, we get,
x gallons of 80 % + 80 gallons of 15 % = (x + 80) gallons of 70 %

Thus 440 gallons of 80 % antifreeze solution must be mixed
Answer:
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