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drek231 [11]
3 years ago
12

Use long division to find the quotient below.(4x3 + 11x2 + 9) ÷ (x + 3)​

Mathematics
1 answer:
Mila [183]3 years ago
4 0

Answer:

4x³+11x²+9/x+3

Step-by-step explanation:

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bills normal temperature is 98.6 today ballistic and has a temperature of 104.3 how many degrees above his normal temperature is
kkurt [141]

Answer:

Today's temperature is 5.7 degrees above Bill's normal temperature.

Step-by-step explanation:

Given

Represent the normal temperature with N and today's temperature with T.

Such that:

N = 98.6

T = 104.3

Required

Determine the temperature above the normal temperature

The interpretation of this is to calculate the difference between Bill's normal temperature and Bill's today temperature.

Represent the difference with D

D is calculated as follows:

D = T - N

Substitute values for T and N

D = 104.3 - 98.6

D = 5.7

Hence, today's temperature is 5.7 degrees above Bill's normal temperature.

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3 years ago
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Ugo [173]

Answer:

1) 180 ft / 6 sec

2) 86 mi/5 hr

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4) 93 feet / 5 sec

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3 years ago
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In slope-intercept form what is m=-2, b=8/5
Harman [31]

Answer:

y = -2x + 8/5

Step-by-step explanation:

6 0
3 years ago
A fast-food company is interested in knowing the probability of whether a customer viewed an advertisement for their new special
lord [1]

Answer:

45% probability that a randomly selected customer saw the advertisement on the internet or on television

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a customer saw the advertisement on the internet.

B is the probability that a customer saw the advertisement on television.

We have that:

A = a + (A \cap B)

In which a is the probability that a customer saw the advertisement on the internet but not on television and A \cap B is the probability that the customers saw the advertisement in both the internet and on television.

By the same logic, we have that:

B = b + (A \cap B)

12% saw it on both the internet and on television.

This means that A \cap B = 0.12

20% saw it on television

This means that B = 0.2

37% of customers saw the advertisement on the internet

This means that A = 0.37

What is the probability that a randomly selected customer saw the advertisement on the internet or on television

A \cup B = A + B - (A \cap B) = 0.37 + 0.2 - 0.12 = 0.45

45% probability that a randomly selected customer saw the advertisement on the internet or on television

6 0
3 years ago
What property is expressed below x(3+5y)=3×+5yx​
vlada-n [284]
The distributive property
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3 years ago
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